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Damm [24]
3 years ago
7

1) What happens to the energy carried in the transverse wave as the amplitude increases? *

Physics
1 answer:
Korvikt [17]3 years ago
8 0

Answer:

energy increases, frequency increases

Explanation:

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you are standing on top of a 344 m tall building. A drone operated by your friend is headed straight down, at a speed of 37.0 m/
Kazeer [188]

Answer:

v = 74.0m/s

Explanation:

Look at the photo.

5 0
3 years ago
An electric pump rated 1.5 KW lifts 200kg of water through a vertical height of 6m in 10 secs: way is the efficiency of the pump
ruslelena [56]

Answer:

80%

Explanation:

Efficiency = Power output / Power input × 100 %

To calculate efficiency we need to find power output of electric pump.

We can use,

Work done = Energy change

Work done per second = Energy change per second

Work done per second = Power

Therefore, Power = Energy change per second

                              = Change in potential energy of water per second

                              =mgh / t

                              = 200× 10×6 / 10

                              = 1200 W = 1.2 kW

Now use the first equation to find efficiency,

Efficiency = \frac{1.2}{1.5} × 100%

                = 80 %

8 0
3 years ago
When the starter motor on a car is engaged, there is a 320 A current in the wires between the battery and the motor. Suppose the
Salsk061 [2.6K]

Answer:

0.5

Explanation:

because it is V uwbsusvegwjosnfvehdbuxbdusndgdghqbwbwbbeuehdbdhdhdhdudhdhdudhdnskowoqllqlqlqnebe

8 0
2 years ago
A __ is used to measure air pressure.
larisa86 [58]
A barometer is used to measure air pressure!
8 0
3 years ago
Read 2 more answers
A series of optical telescopes produced an image that has a resolution of about 0.00350 arc second.
Mila [183]

Answer:

The smallest diameter is D =122 \ m

Explanation:

From the question we are told that

       The resolution of the telescope is \theta  =  0.00350 \ arc \ second

           The wavelength is  \lambda = 1.70 \mu m = 1.70 *10^{-6} \ m

From the question we are told that

        1 arc \ sec = \frac{1}{3600^o}

So      0.00350 \ arc \ second = x

Therefore

             x =  0.00350  *  \frac{1}{3600 }

              x = ( 9.722*10^{-7} )^o

Now  1^o  =  \frac{\pi}{180}

   So  (9.722*10^{-7})^o =  \theta

  =>    \theta  =  (9.722*10^{-7}) * \frac{\pi}{180}

           \theta  =  1.69*10^{-8} rad

The smallest diameter is mathematically represented  as

          D = \frac{1.22 \lambda }{\theta  }

substituting values

           D = \frac{1.22 * 1.7 *10^{-6}} {1.69 *10^{-8}  }

           D =122 \ m

   

6 0
3 years ago
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