All categories

3 years ago

An 8 Ω resistor is connected to a battery. The current that flows in the circuit is 2 A. Calculate the voltage of the battery.

1 answer:

Crank3 years ago

7 0

Here is the highly detailed, arcane, complex, technical form of Ohm's Law that is needed in order to answer this question ===> V = I · R .

Voltage = (current) x (resistance)

Voltage = (2 Ampere) x (8 Ω)

<em>Voltage = 16 volts</em>

You might be interested in

61. A physics student has a single-occupancy dorm room. The student has a small refrigerator that runs with a current of 3.00 A

Mademuasel [1]

Answer:

Part a)

$percentage = 21.3$ %

Part b)

$percentage = 2.13 \times 10^{-5}$ %

Explanation:

As we know that total power used in the room is given as

$P = P_1 + P_2 + P_3 + P_4$

here we have

$P_1 = (110)(3) = 330 W$

$P_2 = 100 W$

$P_3 = 60 W$

$P_4 = 3 W$

$P = 330 + 100 + 60 + 3$

$P = 493 W$

Part a)

Since power supply is at 110 Volt so the current obtained from this supply is given as

$110\times i = 493$

$i = 4.48 A$

now resistance of transmission line

$R = \frac{\rho L}{A}$

$R = \frac{(2.8 \times 10^{-8})(10\times 10^3)}{\pi(4.126\times 10^{-3})^2}$

$R = 5.23 \ohm$

now power loss in line is given as

$P = i^2 R$

$P = (4.48)^2(5.23)$

$P = 105 W$

Now percentage loss is given as

$percentage = \frac{loss}{supply} \times 100$

$percentage = \frac{105}{493} \times 100$

$percentage = 21.3$ %

Part b)

now same power must have been supplied from the supply station at 110 kV, so we have

$110 \times 10^3 (i ) = 493$

$i = 4.48\times 10^{-3} A$

now power loss in line is given as

$P = i^2 R$

$P = (4.48 \times 10^{-3})^2(5.23)$

$P = 1.05 \times 10^{-4} W$

Now percentage loss is given as

$percentage = \frac{loss}{supply} \times 100$

$percentage = \frac{1.05 \times 10^{-4}}{493} \times 100$

$percentage = 2.13 \times 10^{-5}$ %

6 0

3 years ago

Two cars collide inelastically and stick together after the collision. Before the collision, the magnitudes of their momenta are

dolphi86 [110]

Answer:

a) P1+P2

Explanation:

The magnitude of their combined momentum is just the addition of each momentum, because in this case of inelastic collision, the kinetic energy of the two cars are both converted to some form of energy because the velocity of both cars becomes zero, i.e., V=0, making P = mv = 0, this means the magnitude of P1 + P2 = 0.

3 0

2 years ago

A is a non-contact breaking of the basketball rules <br>

ElenaW [278]

A foul occurs when a player or coach breaks a rule covering either contact with an opposing player of unsportsmanlike action. Basketball is a so-called non-contact sport but basketball rules recognize that is not really possible to have 10 players running around a small area without making some contact.

7 0

3 years ago

What characteristics of life can you identify in this figure?

kodGreya [7K]

•responsiveness to the environment;
•growth and change;
•ability to reproduce;
•have a metabolism and breathe;
•maintain homeostasis;
•being made of cells; and.
•passing traits onto offspring.

8 0

3 years ago

An isotope of Uranium, Z = 92 and A = 235, decays by emitting an alpha particle. Calculate the number of neutrons in the nucleus

stepan [7]

Answer:

141

Explanation:

The atomic number (Z) corresponds to the number of protons:

Z = p

while the mass number (A) corresponds to the number of protons+neutrons:

A = p + n

So the number of neutrons in a nucleus is equal to the difference between mass number and atomic number:

n = A - Z

For the initial nucleus of Uranium, Z = 92 and A = 235, so the initial number of neutrons is

n = 235 - 92 = 143

An alpha particle carries 2 protons and 2 neutrons: so, when the isotope of Uranium emits an alpha particle, it loses 2 neutrons. Therefore, the number of neutrons after the decay will be

n = 143 - 2 = 141

4 0

3 years ago