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Nataly_w [17]
2 years ago
10

A jet plane lands with a speed of 87 m/s and can accelerate at a maximum rate of −4.10 m/s2 as it comes to rest. (a) From the in

stant the plane touches the runway, what is the minimum time needed before it can come to rest?
Physics
1 answer:
garri49 [273]2 years ago
7 0

Answer:

21.22s

Explanation:

initial velocity u=87m/s

acceleration a=-4.10 m/s²

velocity v=0

time t=?

From Newton's first law of motion

V=u+at

0=87-4.10t

-87=-4.1t

t= -87/-4.1

t= 21.22 s

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As the energy in the system is conserved

mgh=I\frac{\omega^2}{2}\\\Rightarrow mgh=m(\frac{1}{12}+0.0784)\frac{\omega^2}{2}\\\Rightarrow gh=(\frac{1}{12}+0.0784)\frac{\omega^2}{2}\\\Rightarrow \omega=\sqrt{\frac{2gh}{\frac{1}{12}+0.0784}}\\\Rightarrow \omega=\sqrt{\frac{2\times 9.81\times 0.28}{\frac{1}{12}+0.0784}}\\\Rightarrow \omega=5.82812\ rad/s

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