Answer:
a rock of 50kg should be placed =drock=0.5m from the pivot point of see saw
Explanation:
τchild=τrock
Use the equation for torque in this equation.
(F)child(d)child)=(F)rock(d)rock)
The force of each object will be equal to the force of gravity.
(m)childg(d)child)=(m)rockg(d)rock)
Gravity can be canceled from each side of the equation. for simplicity.
(m)child(d)child)=(m)rock(d)rock)
Now we can use the mass of the rock and the mass of the child. The total length of the seesaw is two meters, and the child sits at one end. The child's distance from the center of the seesaw will be one meter.
(25kg)(1m)=(50kg)drock
Solve for the distance between the rock and the center of the seesaw.
drock=25kg⋅m50kg
drock=0.5m
False
You cannot see behind you, therefore it is not in your cone of vision.
Answer:
λ = 8.716 mm
Explanation:
Given:
- d = 10 cm
- Q >= 5 degrees
Find:
- Find the shortest wavelength of light for which this apparatus is useful
Solution:
- The formula that relates the split difference and angle of separation between successive fringes is given by:
d*sin(Q) = n*λ
Where,
λ: wavelength
d: split separation
Q: angle of separation between successive fringes
m: order number.
- Since this apparatus only shows the first order light so m =1
- the shortest possible wavelength corresponds to:
d*sin(Q) = λ
λ = 0.1*sin(5)
λ = 8.716 mm
