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vlabodo [156]
2 years ago
5

What will be the answer if we use the distributive property: 2(9*9-7*8-9*3+3)

Mathematics
1 answer:
snow_lady [41]2 years ago
6 0
2(81-56-27+3)
162-112-54+3= -1
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4. Identify the zeros and the graph of the function y = x(x − 2)(x + 5).
Natalka [10]

The zeros of

y = x(x + 2)(x + 5)y=x(x+2)(x+5)

are

x=0,x=-2,x=-5x=0,x=−2,x=−5

EXPLANATION

The given function is

y = x(x + 2)(x + 5)y=x(x+2)(x+5)

To find the zeros of the above function, we just have to equate the function to zero and solve for x.

x(x + 2)(x + 5) = 0x(x+2)(x+5)=0

This implies that,

x = 0 \: \: or \: x + 2 = 0 \:or \: x + 5 = 0x=0orx+2=0orx+5=0

x = 0 \: \: or \: x = - 2\:or \: x = - 5x=0orx=−2orx=−5

To graph the above function, we need to consider the multiplicity.

We can see that the multiplicity of the roots are odd. This means that, the graph crosses the x-axis at each x-intercept.

We also need to consider the position of the graph on the following intervals,

x < - 5x<−5

When

x = - 10x=−10

y = - 10( - 8)( - 5) \: < \: 0y=−10(−8)(−5)<0

The graph is below the x-axis.

- 5 \: < \: x \: < \: - 2−5<x<−2

When

x = - 3x=−3

y = - 3(2)( - 1) \: > 0y=−3(2)(−1)>0

The graph is above the x-axis.

- 2 \: < \: x < \: 0−2<x<0

when

x = - 1x=−1

y = -1(1)(4) \: < \: 0y=−1(1)(4)<0

The graph is below the x-axis.

Finally the interval,

x \: > \: 0x>0

when

x = 1x=1

y = 1(3)(6) \: > \: 0y=1(3)(6)>0

The graph is above the x-axis.

We can now use the above information to sketch graph as shown in the diagram above

3 0
2 years ago
Pls answer asap!!!!!!!!!!!!!!!!!!!!!!!!!
ki77a [65]

Answer:

2rr

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
find the difference between the sum of all eight positive intergral divisors of 66 and the sum of all eight positive integral di
katrin [286]

The difference between the sum of all eight positive integral divisors of 66 and the sum of all eight positive integral divisors of 70 is zero.

<h3>How to find the difference between the integral divisors?</h3>

First let's find the integral divisors. We can write 66 as a product of prime numbers as:

66 = 33*2 = 2*3*11

Then the integral divisors of 66 are:

2

3

11

2*3 = 6

2*11 = 22

3*11 = 33

1 (trivially)

66 (trivially)

The sum gives:

2 + 3 + 11 + 6 + 22 +33 + 1 + 66 = 144

For 70 we have:

70 = 7*10 = 2*5*7

Then the integral divisors are:

1

70

2

5

7

2*5 = 10

2*7 = 14

5*7 = 35

The sum gives:

1 + 70 + 2 +5 + 7 + 10 + 14 + 35 = 144

Then the difference between these two sums is:

144 - 144 = 0

If you want to learn more about integral divisors:

brainly.com/question/4785696

#SPJ1

7 0
1 year ago
What is the measures of angle ECD? Please show work.
bazaltina [42]

The anser is 40

the resense is verticle angle are congrounent.

6 0
3 years ago
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Complete the square to re-write the quadratic function in vertex form: y=x2-x+3
Anna [14]

Answer:

Step-by-step explanation:

hello :

note : the vertex form is :

ax²+bx+c = a(x+(b)/(2a))²-  delta/4a²   and   delta = b²- 4ac

in this exercice you have : a =1    b = -1   and  c= 3

continu ..........

5 0
2 years ago
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