Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.
Solution :
According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.
or,
..........(1)
where,
= rate of effusion of nitrogen gas = 
= rate of effusion of sulfur dioxide gas = ?
= molar mass of nitrogen gas = 28 g/mole
= molar mass of sulfur dioxide gas = 64 g/mole
Now put all the given values in the above formula 1, we get:
Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.
Answer:
A. 2Na + 2H₂O → 2NaOH + H₂
Explanation:
When sodium is reacted with water, a single replacement reaction occurs. The product of the reaction is typically sodium hydroxide and hydrogen gas.
Reactants:
Sodium + water
Product:
Sodium hydroxide + hydrogen gas
So;
2Na + 2H₂O → 2NaOH + H₂
Sulfur is not a transition metal so it does not need a Roman numeral the correct answer is Trisulfur Dichloride
