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ad-work [718]
3 years ago
13

What is one similarity between the lungs and capillaries? (5 points) They are both activated by inhalation. They are both involv

ed in gas exchanges. They are both part of the circulatory system. They are both regulated by the heart.
Chemistry
2 answers:
djverab [1.8K]3 years ago
7 0

Answer:

They are both involved in gas exchanges.

Explanation:

This is the answer because:

1) Gas exchange takes place in the millions of alveoli in the lungs and the capillaries that envelop them. Inhaled oxygen moves from the alveoli to the blood in the capillaries, and carbon dioxide moves from the blood in the capillaries to the air in the alveoli.

2) Also, capillaries are located inside the lungs. Therefore, whenever we breathe in air we exchange gasses.

Hope this helps! :D

SIZIF [17.4K]3 years ago
6 0

Answer:

They are both involved in gas exchanges.

Explanation:

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What determines an object’s ability to float?
Nezavi [6.7K]
Simply put, density is how tightly “stuff” is packed into a defined space.

For example, a suitcase jam-packed with clothes and souvenirs has a high density, while the same suitcase containing two pairs of underwear has low density. Size-wise, both suitcases look the same, but their density depends on the relationship between their mass and volume.
Mass is the amount of matter in an object.
Volume is the amount of space that an object takes up in three dimensions.

Density is calculated using the following equation: Density = mass/volume or D = m/v.

If something is heavy for its size, it has a high density. If an object is light for its size it has a low density.

The relative densities of an object and the liquid it is placed in determine whether that object will sink or float.
3 0
2 years ago
What mass of solute is contained in 25.4 ml of a 1.56 m potassium bromide solution?
mash [69]
Answer is: mass of <span>potassium bromide is 4.71 grams.
V(KBr) = 25.4 mL </span>÷ 1000 mL/L = 0.0254 L, volume of solution.
c(KBr) = 1.56 mol/L.
n(KBr) = c(KBr) · V(KBr).
n(KBr) = 1.56 mol/L  0.054 L.
n(KBr) = 0.0396 mol, amount of substance.
m(KBr) = n(KBr) · M(KBr).
m(KBr) = 0.0396 mol · 119 g/mol.
m(KBr) = 4.71 g.
M - molar mass.
3 0
3 years ago
Read 2 more answers
True or Flase: dissolving salt in distilled water creates a homogeneous mixture.
chubhunter [2.5K]

Answer:

true

Explanation:

7 0
3 years ago
Read 2 more answers
Jamie rolls a 6-sided die 30 times and determines that the experimental probability of rolling a 2 is Start Fraction 1 over 15 E
anyanavicka [17]

Answer:

Conduct more trials

Explanation:

Theoretical Probability can be defined as what someone is expecting to happen

Experimental Probability on the other hand, is defined as what actually happens.

Probability is usually calculated in the same way for experimental probability and that of theoretical probability. You divide the total number of possible ways in which a particular outcome can happen, by the total number of outcomes itself.

In Experimental probability, the more times a probability is tried, it gets closer and even more closer to theoretical probability.

So, for the question, Jamie should improve the number of tries more, so as to get his experimental probability results to be closer to the theoretical probability result.

8 0
3 years ago
how many formula units of CaCl2 are in 111 g CaCl2? the molar mass of calcium chloride is about 111 g/mol
d1i1m1o1n [39]

There are 6.02 × 10²³ formula units of CaCl2 in 111 g CaCl2. Details about formula units can be found below.

<h3>What is a formula unit?</h3>

Formula unit refers to the empirical formula of an ionic compound for use in stoichiometric calculations.

According to this question, there are 111g of CaCl2. The formula units can be calculated by multiplying the number of moles by Avogadro's number.

no of moles in CaCl2 = 111g ÷ 111g/mol = 1mol

Formula units of CaCl2 = 1mol × 6.02 × 10²³ = 6.02 × 10²³ formula units.

Therefore, there are 6.02 × 10²³ formula units of CaCl2 in 111 g CaCl2.

Learn more about formula units at: brainly.com/question/21494857

#SPJ1

5 0
2 years ago
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