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Setler79 [48]
2 years ago
7

If 165.0g of nitrogen is reacted with 210.0g of hydrogen, what is the theortical yield of the reaction? What is the excess react

ant? What is the limiting reactant? Show your work.​
Chemistry
1 answer:
Alborosie2 years ago
6 0

Answer:

this is your answer 133.0g

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When you sweat a lot the water content of your blood can drop. Your cells have to maintain a certain level of water and salt in
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Write a balanced nuclear equation for the Beta decay of : <br> A. Nitrogen-16<br> B. Potassium-40
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16        16       0
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For the reaction So3 + H2O -&gt; H2SO4, how many grams of sulfur trioxide are required to produce 4.00 mol of sulfuric acid
zalisa [80]

Answer:

320 grams of sulfur trioxide are required to produce 4.00 mol of sulfuric acid.

Explanation:

The balanced reaction is:

SO₃ + H₂O → H₂SO₄

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • SO₃: 1 mole
  • H₂O: 1 mole
  • H₂SO₄: 1 mole

Being the molar mass of each compound:

  • SO₃: 80 g/mole
  • H₂O: 18 g/mole
  • H₂SO₄: 98 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • SO₃: 1 mole* 80 g/mole= 80 grams
  • H₂O: 1 mole* 18 g/mole= 18 grams
  • H₂SO₄: 1 mole* 98 g/mole= 98 grams

Then you can apply the following rule of three: if 1 mole of sulfuric acid is produced by the reaction of 80 grams of sulfur trioxide, 4 moles of sulfuric acid is produced from how much mass of sulfur trioxide?

mass of sulfur trioxide= \frac{4 moles of sulfuric acid*  80 grams of sulfur trioxide}{1 mole of sulfuric acid }

mass of sulfur trioxide= 320 grams

<u><em>320 grams of sulfur trioxide are required to produce 4.00 mol of sulfuric acid.</em></u>

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3 years ago
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