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Feliz [49]
3 years ago
7

The Topology Taxi Company charges 2.80 for the first fifth of a mile and 0.45 for each additional fifth of a mile. Find a linear

function which models the taxi fare F as a function of the number of miles driven, m .
Mathematics
1 answer:
cestrela7 [59]3 years ago
8 0

Answer:

F=2.2375+2.25m is a linear function which models the taxi fare F as a function of the number of miles driven, m

Step-by-step explanation:

a+0.25=m

a=m-0.25

a/0.20=d

(m-0.25)/0.20=d

F=2.80+0.45(m-0.25)/0 20

=2.80+2.25(m-0.25)

=2.80+2.25m-0.5625

=2.80-0.5625+2.25m

F=2.2375+2.25m

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I need the answer for 4. and 5.
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Exercise 4

A grow from 13.1 millions to 14.4 millions means to grow

14.4-13.1 = 1.3

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\dfrac{x}{100}\cdot 13.3 = 1.3

Solving for x, you have

x = \dfrac{1.3 \cdot 100}{13.3} \approx 9.92

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3 years ago
The results of a national survey showed that on average, adults sleep 6.7 hours per night. Suppose that the standard deviation i
Roman55 [17]

Answer:

a) Atleast 75%

b) Atleast 88.9%

c) 95%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.7

Standard Deviation, σ = 1.6

Chebyshev's Theorem:

  • Atleast 1 - \dfrac{1}{k^2} percent of data lies within k standard deviation of mean.

Empirical Rule:

  • Almost all the data lies within 3 standard deviation for a normal data.
  • Around 68% of data lies within 1 standard deviation of mean.
  • Around 95% of data lies within 2 standard deviation of mean.
  • Around 99.7% of data lies within 3 standard deviations o mean.

a) minimum percentage of individuals who sleep between 3.5 and 9.9 hours

3.5 = \mu - 2\sigma = 6.7 - 2(1.6)\\9.9 = \mu + 2\sigma = 6.7 + 2(1.6)

We have to find the percent of data lying within 2 standard deviation of mean.

Putting k =  2

1 - \dfrac{1}{(2)^2} = 0.75 = 75\%

Atleast 75% of of individuals who sleep between 3.5 and 9.9 hours.

b) minimum percentage of individuals who sleep between 2.7 and 10.7 hours

2.7 = \mu - 3\sigma = 6.7 - 3(1.6)\\10.7 = \mu + 3\sigma = 6.7 + 3(1.6)

We have to find the percent of data lying within 3 standard deviation of mean.

Putting k =  3

1 - \dfrac{1}{(3)^2} = 0.889 = 88.9\%

Atleast 88.9% of of individuals who sleep between 2.7 and 10.7 hours.

c)  percentage of individuals who sleep between 3.5 and 9.9 hours per day.

Thus, we have to find the percentage of data lying within 2 standard deviation.

By empirical rule, around 95% of data lies within 2 standard deviation.

Thus, 95% of of individuals who sleep between 3.5 and 9.9 hours.

This is higher than the percentage obtained from Chebyshev's rule.

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