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Elanso [62]
3 years ago
5

What are the common approximations made in the analysis of heat exchangers?

Engineering
1 answer:
Oksanka [162]3 years ago
7 0

Answer: making sure that they are up to date

Explanation:

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a) Complete the following methods description using the correct tense for the verb in brackets. (This student is using passive v
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Each of the metal specimens HAS an indentation near the center to ensure that the fracture point would occur in this region. Tension tests WERE CONDUCTED as follows. Two pieces of reflective tape WERE PLACED approximately 1 inch apart in the center of the specimen where the indentation 4 WAS LOCATED. The width and the thickness of the specimen at this location WAS MEASURED using a Vernier caliper. Then the specimen WAS SECURED in the MTS Load Frame. A laser extensometer WAS PLACED into position to measure the deformation of the specimen. The laser extensometer WAS USED to measure the original distance between the pieces of reflective tape. The MTS WAS SET to elongate the specimen one tenth of an inch every minute.

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3 years ago
A radio antenna 326 m in diameter receives a radio signal from a very distant object at perpendicular incidence. The radio signa
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Assume that the antenna absorbs all the radiation that falls on the disk and calculate the power in Watts received by the antenna are the (a) 3.0e-8.

<h3>What is perpendicular with examples?</h3>

Two awesome traces intersecting every different at 90° or a proper perspective are referred to as perpendicular traces. Here, AB is perpendicular to XY due to the fact AB and XY intersect every different at 90°. The  traces are parallel and do now no longer intersect every different. They can in no way be perpendicular to every different.

Read more about the perpendicular :

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6 0
2 years ago
Technician A says that the enable criteria are the criteria that must be met before the PCM completes a monitor test. Technician
DENIUS [597]

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"A"

Explanation:

5 0
3 years ago
A divided multilane highway in a recreational area has four lanes (two lanes in each direction) and is on rolling terrain. The h
sertanlavr [38]

Answer:

Explanation:

Before: PT= 0.10, PB= 0.03 (given) ET = 2.5 ER = 2.0 (Table 6.5)

fHV= 0.847 (Eq. 6.5) PHF = 0.95, fp= 0.90, N=2, V = 2200 (given)

vp= V/[PHF⋅fHVTB⋅fp⋅N] = 1518.9 (Eq. 6.3)

BFFS = 50+5, BFFS =55 (given) fLW= 6.6

TLC=6+3=9 fLC= 0.65

fM= 0.0

fA= 1.0

FFS = BFFS −fLW−fLC–fM–fA= 46.75 (Eq. 6.7)

Use FFS=45 D= vp/S = 33.75pc/mi/ln Eq (6.6)

After: fA= 3.0

FFS = BFFS −fLW−fLC–fM–fA= 44.75 (Eq. 6.7)

Use FFS=45 Vnew= 2600 Vp= Va/[PHF⋅fHB⋅fp⋅N] = 1795 (Eq. 6.3) D= vp/S = 39.89pc/mi/ln

8 0
3 years ago
Can somebody help me with that
skelet666 [1.2K]

Answer:

I think it's 23 ohms.

Explanation:

Not entirely sure about it.

hope this helps

4 0
3 years ago
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