Answer:
a) 280MPa
b) -100MPa
c) -0.35
d) 380 MPa
Explanation:
GIVEN DATA:
mean stress
stress amplitude
a)
--------------1
-----------2
solving 1 and 2 equation we get
b)
c)
stress ratio
d)magnitude of stress range
= 280 -(-100) = 380 MPa
Answer:
676 ft
Explanation:
Minimum sight distance, d_min
d_min = 1.47 * v_max * t_total where v_max is maximum velocity in mi/h, t_total is total time
v_max is given as 50 mi/h
t_total is sum of time for right-turn and adjustment time=8.5+0.7=9.2 seconds
Substituting these figures we obtain d_min=1.47*50*9.2=676.2 ft
For practical purposes, this distance is taken as 676 ft
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Answer:
The efficiency of this ideal and reversible engine is 85 percent.
The efficiency of the Carnot cycle represents the efficiency of a thermal machine with no irreversibilities, hence, it is impossible for any real engine operating between the two reservoirs cannot be more efficient than this engine.
Explanation:
Let assume that the temperature of the atmosphere is 300 K. From Thermodynamics we know that the efficiency of the Carnot's cycle (), dimensionless, is:
(1)
Where:
- Temperature of the kerosene combustor (hot reservoir), measured in kelvins.
- Temperature of the atmosphere (cold reservoir), measured in kelvins.
If we know that and , then the efficieny of this ideal and reversible engine is:
The efficiency of this ideal and reversible engine is 85 percent.
The efficiency of the Carnot cycle represents the efficiency of a thermal machine with no irreversibilities, hence, it is impossible for any real engine operating between the two reservoirs cannot be more efficient than this engine.