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Answer:
2.135
Explanation:
Lets make use of these variables
Ox 16.5 kpsi, and Oy --14,5 kpsi
To determine the factor of safety for the states of plane stress. We have to first understand the concept of Coulomb-Mohr theory.
Mohr–Coulomb theory is a mathematical model describing the response of brittle materials such as concrete, or rubble piles, to shear stress as well as normal stress.
Please refer to attachment for the step by step solution.
Answer:
Detailed working is shown
Explanation:
The attached file shows a detailed step by step calculation..
Answer:
number of pulses produced = 162 pulses
Explanation:
give data
radius = 50 mm
encoder produces = 256 pulses per revolution
linear displacement = 200 mm
solution
first we consider here roll shaft encoder on the flat surface without any slipping
we get here now circumference that is
circumference = 2 π r .........1
circumference = 2 × π × 50
circumference = 314.16 mm
so now we get number of pulses produced
number of pulses produced =
× No of pulses per revolution .................2
number of pulses produced =
× 256
number of pulses produced = 162 pulses
Answer:
The resultant moment is 477.84 N·m
Explanation:
We note that the resultant moment is given by the moment about a given point
The length of the sides of the formed triangles are;
l = sin(40°) × 4/sin(110°) ≈ 2.736
Taking the moment about the lower left hand corner of the figure, with the convention that clockwise moments are positive, we have;
The resultant moment, ∑m, is given as follow;
∑M = 250 N × 4 m + 400 N × cos(40°) × 4 m - 400 N × cos(40°) × 2 m + 400 N × sin(40°) × 2 m × tan(40°) - 600 N × cos(40°) × 2 m - 600 N× sin(40°) × 2 m × tan(40°) = 477.837084 N·m
Therefore, the resultant moment, ∑m ≈ 477.84 N·m clockwise.