Answer:
The shaft work generated per kilogram is 
Explanation:
Given:
Temperature 
K
Initial Pressure 
MPa
Final pressure 
MPa
From the table superheated,
and 
Work done by shaft is,
But here efficiency is 0.56,
So work generated per kg is,
Work = 
Work = 
Therefore, the shaft work generated per kilogram is
Answer: it’s called a saw or see saw
Explanation: it works by cutting a tree, wood, tile, etc.
The correct answer would be d
The objects will not move towards or away from each other
Hope this helps
D i took this hope it helps
Answer:
(a) ΔU = 125 kJ
(b) ΔU = -110 kJ
Explanation:
<em>(a) Suppose that 150 kJ of work are used to compress a spring, and that 25 kJ of heat are given off by the spring during this compression. What is the change in internal energy of the spring during the process?</em>
<em />
The work is done to the system so w = 150 kJ.
The heat is released by the system so q = -25 kJ.
The change in internal energy (ΔU) is:
ΔU = q + w
ΔU = -25 kJ + 150 kJ = 125 kJ
<em>(b) Suppose that 100 kJ of work is done by a motor, but it also gives off 10 kJ of heat while carrying out this work. What is the change in internal energy of the motor during the process?</em>
<em />
The work is done by the system so w = -100 kJ.
The heat is released by the system so q = -10 kJ.
The change in internal energy (ΔU) is:
ΔU = q + w
ΔU = -10 kJ - 100 kJ = -110 kJ
