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nydimaria [60]
3 years ago
5

A package of soup cost $14. an individual cost $2. you will need at least 25 cans.

Mathematics
1 answer:
Naily [24]3 years ago
6 0
Get ten of the packaged kind 
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Stop signs are octagon-shaped. true or false
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Yes, stop signs are octagon shaped. So, true.
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3 years ago
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Is y = 2x - 3 a function
Lostsunrise [7]

Answer: Yes it is a function.

Step-by-step explanation: When trying to find out, you put it into a calculator and can tell by the line if it is a function.

7 0
3 years ago
Will give brainliest!
irakobra [83]

Answer:

Step-by-step explanation:

Remember that our original exponential formula was y = a b x. You will notice that in these new growth and decay functions, the b value (growth factor) has been replaced either by (1 + r) or by (1 - r). The growth "rate" (r) is determined as b = 1 + r.

An exponential function of a^x (a>0) is always ln(a)*a^x, as a^x can be rewritten in e^(ln(a)*x). By deriving, the term (ln(a)) gets multiplied with a^x. The derivative shows, that the rate of change is similiar to the function itself. For 0<a<1, ln(a) becomes negative and so is the rate of change.

Linear models are used when a phenomenon is changing at a constant rate, and exponential models are used when a phenomenon is changing in a way that is quick at first, then more slowly, or slow at first and then more quickly.

6 0
3 years ago
Could yall help please
ser-zykov [4K]

Answer:

C

Step-by-step explanation:

As you know, 390% is 3.9. You multiply 3.9*30 and get 117 or something. That rounds to about 120, so C.

I hoped that helped

6 0
3 years ago
Solve the system x+3=22 2x-y=2
steposvetlana [31]

Hello from MrBillDoesMath!

Answer:

x = 19, y = 36

Discussion:

x + 3 = 22     (*)

2x - y = 2      (**)


Subtract 3 from both sides of (*)

x + 3 -3 = 22 = 3 = 19  =>

x = 19


Substitute x= 19 in (**)

2(19) - y = 2 =>

38 - y = 2 =>           (add y to both sides)

38 -y + y = 2 + y =>

38 = 2 + y  =>         (subtract 2 from both sides)

38 -2 = 2 -2 + y =>

36 = y


Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


3 0
3 years ago
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