Answer:
Elias Nebiyu gives seven breads for his eight friends and he continues this give away for three days.
Step-by-step explanation:
3x 7/8 result is attached above.
Dy/dx = y/(x^2)
dy/y = dx/(x^2)
int[dy/y] = int[dx/(x^2)] ... apply integral to both sides
ln(|y|) = (-1/x) + C
|y| = e^{(-1/x) + C}
|y| = e^C*e^(-1/x)
|y| = C*e^(-1/x)
y = C*e^(-1/x)
So you have the correct answer. Nice job.
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Check:
y = C*e^(-1/x)
dy/dx = d/dx[C*e^(-1/x)]
dy/dx = d/dx[-1/x]*C*e^(-1/x)
dy/dx = (1/(x^2))*C*e^(-1/x)
is the expression for the left hand side (LHS)
y/(x^2) = [C*e^(-1/x)]/(x^2)
y/(x^2) = (1/(x^2))*C*e^(-1/x)
is the expression for the right hand side (RHS)
Since LHS = RHS, this confirms the solution for dy/dx = y/(x^2)
Answer:21
Step-by-step explanation:
Find the median. Separate everything above the median into two groups. Take the group with the larger numbers we’ll call this the upper quartile. Find the median of the larger group or upper quartile. Take the group with the smaller numbers, which we’ll call the lower quartile. Find the median of the smaller group or lower quartile. Subtract the median of the lower quartile from the median of the upper quartile and you will find the inner quartile range. In this case, it is 21
Answer:
If the diagonal and the length of the perpendiculars from the vertices are given, then the area of the quadrilateral is calculated as:
Area of quadrilateral = (½) × diagonal length × sum of the length of the perpendiculars drawn from the remaining two vertices.
