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sammy [17]
2 years ago
12

Oliver heated tungsten cylinder weighing 60 g in a hot water bath. While that was heating , he added 40.37 g of distilled water

to a styrofoam cup calorimeter and measures its temperature at 21.3 C. Oliver then added the hat tungsten to the calorimeter and observed a final temperature of 24.9 C. What was the initial temperature, in C of tungsten cylinder. Specific heat of tungsten is 0.132 Specific hest of water is 4.184
Chemistry
1 answer:
Anuta_ua [19.1K]2 years ago
8 0

Answer:

21.12°C

Explanation:

Q = m×c×∆T

Where;

m= mass

c= specific heat capacity

∆T = change in temperature

Qwater = - (Qtungsten)

Note that; the initial temperature of tungsten = final temperature of water

For Water, m= 40.37g, initial temperature=21.3°C, c= 4.184J/g°C

For tungsten, m= 60g, final temperature=24.9°C, c= 0.132J/g°C

(m×c×∆T)water = - (m×c×∆T)tungsten

40.37 × 4.184 × (T-21.3) = - {60 × 0.132 × (24.9-T)}

168.91 (T-21.3) = - { 7.92 (24.9-T)}

168.91T - 3597.8 = - (197.21 - 7.92T)

168.91T - 3597.8 = - 197.21 + 7.92T

168.91T - 7.92T = - 197.21 + 3597.8

160.99T = 3400.59

T = 3400.59/160.99

T = 21.12°C

Therefore, the initial temperature, in °C of tungsten cylinder is 21.12°C

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valentina_108 [34]

Answer:

The same number of molecules, 6.0 × 10²³ molecules.

Explanation:

The amount of any given gas that can be stored in a container depends on the <u>temperature, pressure and volume </u>of the container. It does not depend on the nature (or identity) of the gas.

So if a 10-liter flask contains 6.0 × 10²³ molecules of hydrogen gas, it will contain the same amount of molecules of any other gas when temperature and pressure remain constant.

6 0
3 years ago
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Hope this helps

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3 years ago
Predict the products of the thermal decomposition of strontium nitrate and show the reaction as a word equation.
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yeag

Explanation:

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6 0
2 years ago
For 100.0 mL of a solution that is 0.040M CH3COOH and 0.010 M CH3COO, what would be the pH after adding 10.0 mL 50.0 mM HCl?
damaskus [11]

Answer:

The pH of the buffer is 3.90

Explanation:

The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:

pH = pKa + log [A-] / [HA]

<em>Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.</em>

<em />

To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:

CH3COO- + HCl → CH3COOH + Cl-

<em>The moles of CH3COO- are its initial moles - the moles of HCl added</em>

<em>And moles of CH3COOH are its initial moles + moles HCl added</em>

<em />

Moles CH3COO-:

Initial moles  = 0.100L * (0.010mol / L) = 0.00100moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.000500 moles

Moles CH3COOH:

Initial moles  = 0.100L * (0.040mol / L) = 0.00400moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.003500 moles

pH is:

pH = 4.75 + log [0.000500] / [0.00350]

<em>pH = 3.90</em>

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<h3>The pH of the buffer is 3.90</h3>
3 0
3 years ago
Lol nevermindnevermindnevermindnevermind
Ivenika [448]

Answer:

never what?

Explanation:

you sure you good

8 0
2 years ago
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