How can water change? I or change into a If 1-Heat causes water toi 2-Water that goes into the alr is called tral air makrs wate
r vapor liguld. 4.- Water changes from and back again. 5.-Water moves between the tollquld to water vapor and the sky over and 1 - This movement of water is called the The Water Cycle માં તારા બાપા તેના માથા recriation callclmon sertion or cordlanation > || ?? ના ના કાકાના રાજા પાસ રામ કા મામા ના ડાકલા , કાકા કા કા કાકા ન કામ મ મ હમા થાન ના માધ્યમ ના ધામા ના કાકા અને કામ ન LIVEWORKSHEE
1 answer:
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Answer:
<h2>0.102 L</h2>Explanation:
The new pressure can be found by using the formula for Boyle's law which is
Since we are finding the new volume
From the question we have
We have the final answer as
<h3>0.102 L</h3>Hope this helps you
<u>Answer:</u>
<u>For a:</u> The number of molecules of nitrogen dioxide is
<u>For b:</u> The mass of nitric acid formed is 54.81 grams
<u>For c:</u> The mass of nitric acid formed is 206 grams
<u>Explanation:</u>
The given chemical reaction follows:
- <u>For a:</u>
By Stoichiometry of the reaction:
1 mole of water reacts with 3 moles of nitrogen dioxide
So, 0.250 moles of water will react with of nitrogen dioxide
According to mole concept:
1 mole of a compound contains number of molecules.
So, 0.75 moles of nitrogen dioxide will contain number of molecules
Hence, the number of molecules of nitrogen dioxide is
- <u>For b:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of nitrogen dioxide = 60.0 g
Molar mass of nitrogen dioxide = 46 g/mol
Putting values in equation 1, we get:
By Stoichiometry of the reaction:
3 moles of nitrogen dioxide produces 2 mole of nitric acid
So, 1.304 moles of nitrogen dioxide will produce = moles of nitric acid
Now, calculating the mass of nitric acid from equation 1, we get:
Molar mass of nitric acid = 63 g/mol
Moles of nitric acid = 0.870 moles
Putting values in equation 1, we get:
Hence, the mass of nitric acid formed is 54.81 grams
- <u>For c:</u>
- <u>For nitrogen dioxide:</u>
Given mass of nitrogen dioxide = 225 g
Molar mass of nitrogen dioxide = 46 g/mol
Putting values in equation 1, we get:
- <u>For water:</u>
Given mass of water = 55.2 g
Molar mass of water = 18 g/mol
Putting values in equation 1, we get:
By Stoichiometry of the reaction:
3 moles of nitrogen dioxide reacts with 1 mole of water
So, 4.90 moles of nitrogen dioxide will react with = of water
As, given amount of water is more than the required amount. So, it is considered as an excess reagent.
Thus, nitrogen dioxide is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
3 mole of nitrogen dioxide produces 2 moles of nitric acid
So, 4.90 moles of nitrogen dioxide will produce of nitric acid
Now, calculating the mass of nitric acid from equation 1, we get:
Molar mass of nitric acid = 63 g/mol
Moles of nitric acid = 3.27 moles
Putting values in equation 1, we get:
Hence, the mass of nitric acid formed is 206 grams