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Basile [38]
2 years ago
9

Why do my teacher's overload me with work?

Chemistry
1 answer:
Studentka2010 [4]2 years ago
8 0

Answer:

for you to get smarter

Explanation:

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Gas A effuses 0.68 times as fast as Gas B. If the molar mass of Gas B is 17 g, what is the mass of Gas A?
BartSMP [9]
The mass of gas A is 11.56. i got this answer by 0.68 multiplied by 17.  because in this problem the key word is times.
4 0
3 years ago
9. You have a mini bottle of pure maple syrup. The full container has a mass of 137
cupoosta [38]

Answer:

A

Explanation:EDGE

7 0
3 years ago
If 15.6 grams of copper (ii) chloride react with 20.2 grams of sodium nitrate how many grams of sodium chloride can be formed? W
olasank [31]

Answer:

- 13.56 g of sodium chloride are theoretically yielded.

- Limiting reactant is copper (II) chloride and excess reactant is sodium nitrate.

- 0.50 g of sodium nitrate remain when the reaction stops.

- 92.9 % is the percent yield.

Explanation:

Hello!

In this case, according to the question, it is possible to set up the following chemical reaction:

CuCl_2+2NaNO_3\rightarrow 2NaCl+Cu(NO_3)_2

Thus, we can first identify the limiting reactant by computing the yielded mass of sodium chloride, NaCl, by each reactant via stoichiometry:

m_{NaCl}^{by\ CuCl_2}=15.6gCuCl_2*\frac{1molCuCl_2}{134.45gCuCl_2} *\frac{2molNaCl}{1molCuCl_2} *\frac{58.44gNaCl}{1molNaCl} =13.56gNaCl\\\\m_{NaCl}^{by\ NaNO_3}=20.2gNaNO_3*\frac{1molNaNO_3}{84.99gNaNO_3} *\frac{2molNaCl}{2molNaNO_3} *\frac{58.44gNaCl}{1molNaCl} =13.89gNaCl

Thus, we infer that copper (II) chloride is the limiting reactant as it yields the fewest grams of sodium chloride product. Moreover the formed grams of this product are 13.56 g. Then, we take 13.56 g of sodium chloride to compute the consumed mass sodium nitrate as it is in excess:

m_{NaNO_3}^{by\ NaCl}=13.56gNaCl*\frac{1molNaCl}{58.44gNaCl}*\frac{2molNaNO_3}{2molNaCl} *\frac{84.99gNaNO_3}{1molNaNO_3}=19.72gNaNO_3

Therefore, the leftover of sodium nitrate is:

m_{NaNO_3}^{leftover}=20.2g-19.7g=0.5gNaNO_3

Finally, the percent yield is computed via:

Y=\frac{12.6g}{13.56g} *100\%\\\\Y=92.9\%

Best regards!

6 0
2 years ago
Which has the greatest atomic number , boron or lithium ?
Kay [80]
Use the periodic table , it should be the long decimal if u look it up
4 0
3 years ago
Read 2 more answers
A sample of chlorine gas fills a vessel at a temperature of 37oC. The vessel has a volume of 3L and experiences a pressure of 3a
Iteru [2.4K]

Answer:

25.1 g is the mass of chlorine in the sample

Explanation:

P . V = n . R . T

We apply the Ideal Gases Law to solve the excersise.

We need to convert the T°C to T°K → 37°C + 273 = 310K

We replace data: 3 atm . 3L = n . 0.082 L.atm /mol.K . 310K

9 atm.L / (0.082 L.atm /mol.K . 310K) = n → 0.354 moles

We convert the moles to mass, to reach the answer

0.345 mol . 70.9g / 1mol = 25.1 g

7 0
3 years ago
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