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3 years ago

Without multiplying, order the following products from least to greatest. 23* 2/2 23* 1/4 23* 13/5

1 answer:

7 0

Answer:

From least to greatest

23* 1/4, 23* 2/2, 23* 13/5

Explanation

In order to do this without multiplication, place the fractions in ascending order.

The denominators of these fractions have 20 as a common multiple.

2/2 • 10 = 20/20

1/4 • 5 = 5/20

13/5 • 4 = 52/20

From this it logically follows that the fractions in ascending order are:

1/4, 2/2, 13/5

Therefore the products in ascending order are:

23* 1/4, 23* 2/2, 23* 13/5

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Which of the following sets of lengths could not be the side lengths of a triangle?

docker41 [41]

To find out if the three side lengths can create a triangle, the three smaller lengths must be greater than the longer length.

$\bf~Option~A$

$\sf~3~meters,5~meters,7~meters$

$\sf3+5=8>7$

So this can create a triangle.

$\bf~Option~B$

$\sf1~yard,1.25~yards,1.5~yards$

$\sf1+1.25=2.25>1.5$

So this can create a triangle.

$\bf~Option~C$

$\sf5~inches,10.5~inches,17~inches$

$\boxed{\sf5+10.5=15.5$

So this cannot create a triangle.

$\bf~Option~D$

$\sf15~millimeters,18~millimeters,30~millimeters$

$\sf15+18=33>30$

So this can create a triangle.

Therefore, your answer is Option C.

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3 years ago

What is the length of line segment PQ? 4 units 5 units 6 units 9 units

makkiz [27]

Hello!

I was looking for this answer as well, but I took the quiz and got it correct. The answer is 5 units.

good luck!

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4 years ago

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(9 x 10) + (20x + 21) = 571 What does (x) equal

creativ13 [48]

(9 × 10) + (20x + 21) = 571
90 + 20x + 21 = 571
111 + 20x = 571
- 111
20x = 460
÷ 20
x = 23
I hope this helps!

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3 years ago

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What is another name for ray AE ?

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Answer:

Step-by-step explanation:

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3 years ago

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50,000 contestants participate in an on-line game. The game randomly eliminates 20% of the contestants each day. Determine the n

irga5000 [103]

Answer:10,486 contestants

Step-by-step explanation:

First day:

Total number of contestants at the beginning = 50,000

After first day, 20% 0f 50,000 are removed.

That is, (20/100)×50,000 = 10,000

Contestants remaining after first day = 50,000-10,000 = 40,000

Second day:

Contestants= 40,000

20% removed

That is (20/100)×40000=8000

Balance =40000-8000=32,000

Third day:

Contestants= 32000

20% removed

That is (20/100)×32000=6400

Balance =32000-6400=25,600

Fouth day:

Contestants= 25,600

20% removed

That is (20/100)×25,600=5,120

Balance =25,600-5,120=20,480

Fifth day:

Contestants= 20,480

20% removed

That is (20/100)×20,480=4096

Balance =20,480-4096=16,384

Sixth day:

Contestants= 16,384

20% removed

That is (20/100)×16,384=3276.8

Balance =16,384-3276.8=13,107.2

Seventh day:

Contestants= 13,107.2

20% removed

That is (20/100)×13,107.2=2621.44

Balance =13107.2-2621.44=10485.76

Therefore, number of contestants remaining after one week equals 10,486.

6 0

3 years ago