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3 years ago

A TV has a power of 130 watts and an efficiency of 80 percent. How much

Physics

1 answer:

elena55 [62]3 years ago

3 0

Answer:

I think A. 104.0 W is wasted add heat.

Explanation:

130 W x 80% = 130 W x 0.8

= 104.0 W

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It's easy!but help..

zimovet [89]

Answer:

The marble as lost energy due to gravity, air resistance (if there is air), and the centripetal force when going around that loop.

Explanation:

Also a little in heat but that rly doesnt matter

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3 years ago

Susan competes in luge competitions during the winter months. She rides solo on a small sled 3 inches off the ground down icy sl

denis-greek [22]

The distance covered is 30.2 m

Explanation:

The motion of Cynthia is a uniformly accelerated motion (constant acceleration), so we can find the distance covered by using the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

In this problem,

u = 0 (since Cynthia started from rest)

t = 3.2 s

$a=5.9 m/s^2$ is her acceleration

Substituting,

$s=0+\frac{1}{2}(5.9)(3.2)^2=30.2 m$

Learn more about accelerated motion:

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3 years ago

Elements on the periodic table are ordered according to their _________

torisob [31]

Elements are arranged from left to right and top to bottom in order of increasing atomic number.:)

3 0

3 years ago

What day of the year is solar time the same as sidereal time?

Illusion [34]

Answer:

I think the answers March 21

6 0

3 years ago

Read 2 more answers

For fully developed laminar pipe flow in a circular pipe, the velocity profile is u(r) = 2(1-r2 /R2 ) in m/s, where R is the inn

sdas [7]

Answer:

a) $v_{max} = 2\ \textup{m/s}$

b) $v_{avg} = 1\ \textup{m/s}$

c) Q = 1.256 × 10⁻³ m³/s

Explanation:

Given:

The velocity profile as:

$u(r) = 2(1-\frac{r^2}{R^2} )$

Now, the maximum velocity of the flow is obtained at the center of the pipe

i.e r = 0

thus,

$v_{max}=u(0) = 2(1-\frac{0^2}{R^2} )$

$v_{max} = 2\ \textup{m/s}$

Now,

$v_{avg} = \frac{v_{max}}{2}\ \textup{m/s}$

$v_{avg} = \frac{2}}{2}\ \textup{m/s}$

$v_{avg} = 1\ \textup{m/s}$

Now, the flow rate is given as:

Q = Area of cross-section of pipe × $v_{avg}$

Q = $\frac{\pi D^2}{4}\times v_{avg}$

Q = $\frac{\pi 0.04^2}{4}\times 1$

Q = 1.256 × 10⁻³ m³/s

7 0

3 years ago