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Igoryamba
3 years ago
6

Of the following telescopes, which one would best be able to pierce through the Earth's atmosphere and function on the surface o

f the Earth?
Physics
2 answers:
gtnhenbr [62]3 years ago
6 0

Answer:

D.  A radio telescope (hope this helps)

Explanation:

mariarad [96]3 years ago
5 0

Answer:

<em>D</em>

Explanation:

<em>The Earth's atmosphere interferes with radio waves less than any other wavelength, so the best kind of telescope to build on the Earth's surface would be a radio telescope. Although visible light telescopes are often built on Earth, they are usually put as high up as possible, such as on mountaintops, where there is less atmosphere to get in their way. Radio telescopes are usually put as far down as possible, such as in valleys, to block out human-generated radio signals coming from other parts of the surface of the Earth. </em>

<em />

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A point charge q1=2.0μC is located on the positive y axis at y=0.30m, and an identical charge q2 is at the origin. Find the magn
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Answer:

(A) 0.279N at angle 38.02°

(B) 0.701N

(C) 14.19°

Explanation:

(A) The net force on q3 is given as:

F = Fxi + Fyj

Fx is the x component of the force

Fy is the y component of the force

Fx = -F(1, 3)cos(90 - x) + F(2, 3)cos0

Fy = -F(2, 3)cosx - F(2, 3)cos90 = -F(2, 3)cosx

First let us find y and angle x from the diagram.

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y² = 0.25

y = 0.5m

Using SOHCAHTOA to find x,

sinx = 0.4/0.5

x = 53.13°

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F = kqQ/r²

Where k = Coulumbs constant

F(1,3) = (k*q1*q3) / r²

F(1, 3) = (9 * 10^9 * 2.0 * 10^(-6) * 4.0 * 10^(-6)) / (0.5²)

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F(2,3) = (k*q2*q3) / r²

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F(2, 3) = 0.45N

Therefore,

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Fy = 0.288cos53.13

Fy = 0.172N

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The magnitude of the force will be

F(mag) = √(0.22² + 0.172²)

F(mag) = 0.279N

The direction of the force makes will be

tanθ = Fy/Fx

tanθ = 0.172/0.22 = 0.781

θ = 38.02° to the x axis.

(B) q2 = - 2.0 * 10^(-6)

This implies that:

F(2,3) = (k*q2*q3) / r²

F(2, 3) = (9 * 10^9 * -2.0 * 10^(-6) * 4.0 * 10^(-6)) / (0.4²)

F(2, 3) = -0.45N

Therefore,

Fx = -0.288cos36.87 - 0.45

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F(mag) = √((-0.68)² + 0.172²)

F(mag) = 0.701N

(C) The direction of the force makes will be

tanθ = 0.172/0.68

θ = 14.19° to the x axis

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