Answer:
A sled and its rider are moving at a speed of along a horizontal stretch of snow, as Figure 4.24a illustrates. The snow exerts a kinetic frictional force on the runners of the sled, so the sled slows down and eventually comes to a stop. The coefficient of kinetic friction is 0.050. What is the displacement x of the sled?
Data????????????????????????????
Answer:
D would be it
Explanation:
cause none of the rest Makes sense to the book of the picture and I'm 100% sure =)
Answer:
60.2 J
Explanation:
Efficiency is the ratio of work out to work in.
e = Wout / Win
0.86 = Wout / 70 J
Wout = 60.2 J
Answer:
the acceleration of the airplane is 5.06 x 10⁻³ m/s²
Explanation:
Given;
initial velocity of the airplane. u = 34.5 m/s
distance traveled by the airplane, s = 46,100 m
final velocity of the airplane, v = 40.7 m/s
The acceleration of the airplane is calculated from the following kinematic equation;
v² = u² + 2as

Therefore, the acceleration of the airplane is 5.06 x 10⁻³ m/s²