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<span>4. Simplify the expression.
sine of x to the second power minus one divided by cosine of negative x</span>
</span>sin2x+cos2x=1</span> <span>1−sin2x=cos2x<span>
</span>cos2(x)/(sin(x)−csc(x))</span> <span>csc(x)=1/sin(x)</span> <span>cos2(x)/(sin(x)− 1/sin(x))= cos2(x)/((sin2(x)− 1)/sin(x))</span> <span>sin2(x)− 1=-cos2(x)</span> <span>cos2(x)/(( -cos2(x))/sin(x))
=-sin(x)</span>
<span>the answer is the letter a) -sin x
</span><span>5. Find all solutions in the interval [0, 2π). (6 points)
sin2x + sin x = 0
</span> using a graphical tool
the solutions x1=0 x2=pi <span>x3=3pi/2
the answer is the letter </span><span>D) x = 0, π, three pi divided by two</span>
The systems of linear equations have been matched with their respective solutions as shown in the image attached below.
<h3>What is a system of linear equations?</h3>A system of linear equations can be defined as an algebraic equation of the first order that has two (2) variables with each of its term having an exponent of one (1).
In this exercise, you're required to match the systems of linear equations with their respective solutions as shown in the image attached below.
Read more on linear equations here: brainly.com/question/2030026
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If you have a unit circle, it means that you have a circle of radius r = 1 unit. So if we consider the scalene triangle of the figure, its vertical side is the sine of the theta angle and its horizontal side is the cosine of the theta angle. Then to find the hypotenuse of the triangle you use the Pythagorean theorem, thus relating the sine and cosine measures. I attach the solution.
