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Nana76 [90]
3 years ago
12

Solve division problem around answer to nearest hundredth 9.2 / 52.063

Mathematics
1 answer:
kifflom [539]3 years ago
8 0
The nearest hundredth would be 0.17
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Write an equation to model this proportional relationship, where x represents the length of the rectangle and y represents the w
Kay [80]

When Area of rectangle is constant, then the length x is inversely proportional to the width y of the rectangle.

x\propto  \frac{1}{y}

We know that the area of a rectangle is given by the product of the length and width of the rectangle.

Area = Length*Width

In this given problem,

The length of the rerectanglctangle is represented by x

and the width of the rectangle is represented by y

If the area of the rectangle is represented by A now.

So by the formula,

A = x*y

When A is constant then,

x = A/y

\therefore x \propto \frac{1}{y}

So from the above calculation we can conclude that about relation between length and width that,

"When Area of rectangle is constant, then the length x is inversely proportional to the width y of the rectangle."

Learn more about Area here -

brainly.com/question/25292087

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5 0
1 year ago
Write as many equivalent expressions to 3/4(4x-8)+1/4(4x-8)
Deffense [45]

Answer:

4x-8

Step-by-step explanation:

3/4(4x-8)+1/4(4x-8)

12/4x-24/4+4/4x-8/4

3x-6+x-2

3x+x-6-2

4x-8

8 0
3 years ago
Read 2 more answers
A right cylinder has a radius of 5 and a height of 9. What is its surface area?​
harkovskaia [24]

Answer:

B. 140π units²

Step-by-step explanation:

Surface area of a cylinder:

2πrh + 2πr²

2π(5)(9) + 2π(5²)

90π + 50π

140π

5 0
2 years ago
Riddle (o˘◡˘o)
HACTEHA [7]

Answer:

Step-by-step explanation:

The maths teacher because it was the first day back but he was giving a ‘miD YeAr tEsT’

7 0
3 years ago
Read 2 more answers
Plzzzz help and I'll give you brainliest ​
sdas [7]

Step-by-step explanation:

Left hand side:

4 [sin⁶ θ + cos⁶ θ]

Rearrange:

4 [(sin² θ)³ + (cos² θ)³]

Factor the sum of cubes:

4 [(sin² θ + cos² θ) (sin⁴ θ − sin² θ cos² θ + cos⁴ θ)]

Pythagorean identity:

4 [sin⁴ θ − sin² θ cos² θ + cos⁴ θ]

Complete the square:

4 [sin⁴ θ + 2 sin² θ cos² θ + cos⁴ θ − 3 sin² θ cos² θ]

4 [(sin² θ + cos² θ)² − 3 sin² θ cos² θ]

Pythagorean identity:

4 [1 − 3 sin² θ cos² θ]

Rearrange:

4 − 12 sin² θ cos² θ

4 − 3 (2 sin θ cos θ)²

Double angle formula:

4 − 3 (sin (2θ))²

4 − 3 sin² (2θ)

Finally, apply Pythagorean identity and simplify:

4 − 3 (1 − cos² (2θ))

4 − 3 + 3 cos² (2θ)

1 + 3 cos² (2θ)

3 0
3 years ago
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