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brilliants [131]
3 years ago
5

I need help, I don’t need an explanation, just the answer

Mathematics
2 answers:
Phantasy [73]3 years ago
8 0

Answer:

x = 48, y = 16

Step-by-step explanation:

meriva3 years ago
5 0

Answer:

x = 48 \:  \:  \:  \:  \:  \: y = 16

Step-by-step explanation:

y =  - x + 4y

y + x = 4y

y + x - 4y = 0

- 3y + x = 0

- x + 4y = 16

- 3y + x = 0

- 3y =  - x

y =  -  \frac{1}{3} ( - 1)x

y =  \frac{1}{3} x

4 \times ( \frac{1}{3} )x - x = 16

\frac{1}{3}x = 16

x = 48

y =  \frac{1}{3}  \times 48

y = 16

Hope this is correct and helpful

HAVE A GOOD DAY!

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Each result is equally likely to occur!!
7 0
3 years ago
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HELP MEEEEE I NEED TO KNOW THE ANSWER FOR MY QUIZ
ss7ja [257]

Answer: 271.0638298 is - 8,- 3

Step-by-step explanation:

-3y<2+ +18=

6 0
3 years ago
How do you find the limit?
coldgirl [10]

Answer:

2/5

Step-by-step explanation:

Hi! Whenever you find a limit, you first directly substitute x = 5 in.

\displaystyle \large{ \lim_{x \to 5} \frac{x^2-6x+5}{x^2-25}}\\&#10;&#10;\displaystyle \large{ \lim_{x \to 5} \frac{5^2-6(5)+5}{5^2-25}}\\&#10;&#10;\displaystyle \large{ \lim_{x \to 5} \frac{25-30+5}{25-25}}\\&#10;&#10;\displaystyle \large{ \lim_{x \to 5} \frac{0}{0}}

Hm, looks like we got 0/0 after directly substitution. 0/0 is one of indeterminate form so we have to use another method to evaluate the limit since direct substitution does not work.

For a polynomial or fractional function, to evaluate a limit with another method if direct substitution does not work, you can do by using factorization method. Simply factor the expression of both denominator and numerator then cancel the same expression.

From x²-6x+5, you can factor as (x-5)(x-1) because -5-1 = -6 which is middle term and (-5)(-1) = 5 which is the last term.

From x²-25, you can factor as (x+5)(x-5) via differences of two squares.

After factoring the expressions, we get a new Limit.

\displaystyle \large{ \lim_{x\to 5}\frac{(x-5)(x-1)}{(x-5)(x+5)}}

We can cancel x-5.

\displaystyle \large{ \lim_{x\to 5}\frac{x-1}{x+5}}

Then directly substitute x = 5 in.

\displaystyle \large{ \lim_{x\to 5}\frac{5-1}{5+5}}\\&#10;&#10;\displaystyle \large{ \lim_{x\to 5}\frac{4}{10}}\\&#10;&#10;\displaystyle \large{ \lim_{x\to 5}\frac{2}{5}=\frac{2}{5}}

Therefore, the limit value is 2/5.

L’Hopital Method

I wouldn’t recommend using this method since it’s <em>too easy</em> but only if you know the differentiation. You can use this method with a limit that’s evaluated to indeterminate form. Most people use this method when the limit method is too long or hard such as Trigonometric limits or Transcendental function limits.

The method is basically to differentiate both denominator and numerator, do not confuse this with quotient rules.

So from the given function:

\displaystyle \large{ \lim_{x \to 5} \frac{x^2-6x+5}{x^2-25}}

Differentiate numerator and denominator, apply power rules.

<u>Differential</u> (Power Rules)

\displaystyle \large{y = ax^n \longrightarrow y\prime= nax^{n-1}

<u>Differentiation</u> (Property of Addition/Subtraction)

\displaystyle \large{y = f(x)+g(x) \longrightarrow y\prime = f\prime (x) + g\prime (x)}

Hence from the expressions,

\displaystyle \large{ \lim_{x \to 5} \frac{\frac{d}{dx}(x^2-6x+5)}{\frac{d}{dx}(x^2-25)}}\\&#10;&#10;\displaystyle \large{ \lim_{x \to 5} \frac{\frac{d}{dx}(x^2)-\frac{d}{dx}(6x)+\frac{d}{dx}(5)}{\frac{d}{dx}(x^2)-\frac{d}{dx}(25)}}

<u>Differential</u> (Constant)

\displaystyle \large{y = c \longrightarrow y\prime = 0 \ \ \ \ \sf{(c\ \  is \ \ a \ \ constant.)}}

Therefore,

\displaystyle \large{ \lim_{x \to 5} \frac{2x-6}{2x}}\\&#10;&#10;\displaystyle \large{ \lim_{x \to 5} \frac{2(x-3)}{2x}}\\&#10;&#10;\displaystyle \large{ \lim_{x \to 5} \frac{x-3}{x}}

Now we can substitute x = 5 in.

\displaystyle \large{ \lim_{x \to 5} \frac{5-3}{5}}\\&#10;&#10;\displaystyle \large{ \lim_{x \to 5} \frac{2}{5}}=\frac{2}{5}

Thus, the limit value is 2/5 same as the first method.

Notes:

  • If you still get an indeterminate form 0/0 as example after using l’hopital rules, you have to differentiate until you don’t get indeterminate form.
8 0
3 years ago
Sophia puts $250 in the bank with a 2.5% annual interest rate compounded monthly. If Sophia does not touch his money, how much m
Fittoniya [83]

Answer:

<h3> D) $276.26</h3>

Step-by-step explanation:

Deposited amount initially (P) = $250.

Rate of interest(r) = 2.5% compounded monthly = 0.025

Number of years (t) = 4.

Number of months in an year (n) = 12.

Formula for compound interest:

A=P(1+\frac{r}{n})^{nt}.

Plugging values in formula, we get

A= 250(1+\frac{0.025}{12})^{12\times 4}

A= 250(1.00208)^{48}

A= 250\times \:1.10506

A=276.26.

<h3>Therefore, correct option is  D) $276.26.</h3>
7 0
3 years ago
What is the axis of symmetry for f(x) = 2x2 − 4x + 5? (1 point) x = −2 x = −1 x = 1 x = 2
Gnom [1K]

Answer:

y = 2x^2 − 4x + 5

y = 2(x^2 − 2x) + 5

y = 2(x^2 − 2x + 1 - 1) + 5

y = 2(x^2 − 2x + 1) + 5 - 2

y = 2(x - 1)^2 + 3

x = 1 is the axis of symmetry.

Do you agree?



4 0
3 years ago
Read 2 more answers
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