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Yuki888 [10]
3 years ago
10

You roll a standard number cube. Find P(not 4).

Mathematics
2 answers:
docker41 [41]3 years ago
5 0
Number of outcomes in question / total number of possible outcomes

P(not 4)=5/6
ArbitrLikvidat [17]3 years ago
4 0
P (not 4) = 5/6 or 83%
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The rabbit population in a small zoo starts with 150 rabbits. The rabbit population is decreasing at a rate of 15% each week. Wh
Mariulka [41]

Answer:

Option D F(x)=150(0.85)^{x}

Step-by-step explanation:

In this problem we have a exponential function of the form

F(x)=a(b)^{x}

where

F(x) -----> the rabbit population

x ----> the number of weeks

a is the initial value

b is the base

In this problem we have

a=150 rabbits

b=1-r

r=15%=15/100=0.15

so

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substitute the values

F(x)=150(0.85)^{x}

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Step-by-step explanation:

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construct a two column proof proving SM RN, given RM SN and ∠MRS ∠NSR. Submit the entire proof to your instructor.
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3 years ago
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

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3 years ago
3/19​% of a quantity is equal to <br> blank of the quantity.
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Answer:

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