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wolverine [178]
3 years ago
9

If the measure of the angle in the southwest corner of the intersection of Broadway and 21st Street is approximately 105ºwhat is

the measure of the angle in the southwest corner of the intersection of Broadway and 22nd Street?
A: 85 degrees
B: 95 degrees
C: 120 degrees
D: 105 degrees

Mathematics
1 answer:
Karolina [17]3 years ago
5 0

Answer:

95°

Step-by-step explanation:

The angle on the 20TH street and 22ND street must add up to 180° so the answer is 95°

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The gcf of two numbers less than or equal to 12 is 2. Their LCM is 20.What are the numbers?
bixtya [17]

We know:

LCM(a,\ b)=\dfrac{ab}{GCF(a,\ b)}

We have

GCF(a,\ b)=2,\ LCM(a,\ b)=20,\ a\leq12,\ b\leq12

Substitute:

20=\dfrac{ab}{2}\qquad|\cdot2\\\\ab=40

40=1\cdot40=2\cdot20=4\cdot10=5\cdot8

Only 4 and 10 meet the requirements of the question.

--------------------------------------------------------------------

40 and 1 NOT, because 40 > 12

20 and 2 NOT, because 20 > 12

5 and 8 NOT because GCF(5, 8) = 1

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3 years ago
3) Which point is located at (6, 3)?<br><br>A <br>B <br>C <br>D​
maks197457 [2]

Answer:

C

Step-by-step explanation:

because its at 6,3

8 0
2 years ago
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5+(x-5)=x justify each step
max2010maxim [7]

5+(x-5)=x

Simplify the left side by combining like terms:

5 + x - 5 = x

5-5 = 0

x = x

X = All real numbers.

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3 years ago
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Which equation could represent the graph shown below
kaheart [24]

Answer:

f(x) = √(x+1) -2

Step-by-step explanation:

Since you're working with transformed functions, you know that replacing x with x-a in f(x) will translate the graph "a" units to the right. You also know that adding "b" units to the function value will translate the graph "b" units upward.

Here, the graph of f(x) = √x has been translated 1 unit to the left (a=-1) and 2 units down (b=-2). So, the transformed function is ...

f(x) = √(x-(-1)) + (-2)

f(x) = √(x+1) -2 . . . . . . simplify

6 0
4 years ago
OOOO
lbvjy [14]

Step-by-step explanation:

Given bi-quadratic equation is:

x^4+95x^2 -500=0

Substituting x^2=a, given bi-quadratic equation reduces in the form of following quadratic equation:

a^2 +95a -500=0\\

Let us factorize the above quadratic equation:

a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\

Since square root of a negative number cannot be found, so:

x \neq \pm \sqrt{-100}\\

CASE\: (2)\:\\When\: a =5 \implies x^2 =5\\\therefore x=\pm \sqrt{5}\\

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3 years ago
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