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4 years ago

A uniform brick of length 21 m is placed over

Physics

1 answer:

Paha777 [63]4 years ago

6 0

Answer:

15.75 m

Explanation:

First, let's look at the top brick by itself. In order for it not to tip over the bottom brick, its center of gravity must be right at the edge of the bottom brick. So the edge of the top brick must be 10.5 m from the edge of the bottom brick.

Now let's look at both bricks as a combined mass. We know the total length of this combined brick is 10.5 m + 21 m = 31.5 m. And we know that for it to not tip over the edge of the surface, its center of gravity must be at the edge. So the edge of the combined brick must be 31.5 m / 2 = 15.75 m from the edge of the surface.

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3 years ago

PLEASE HELP ME (stop putting links ) Two objects m1 and m2, each with a mass of 5 kg and 6 kg separated by a distance. A third o

BabaBlast [244]

Answer:

Explanation:

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$\displaystyle \frac{GmM}{d^2}$

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3 years ago

Why is it important to develop alternative energy sources

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Answer:

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3 years ago

a skier starts at rest at the top of a hill with 350 J of gravitational potential energy. Assuming energy is conserved, what is

spayn [35]

Answer:

350Joules

Explanation:

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3 years ago

A combined circuit has two resistors in series (27.5 ohms and 33.0 ohms) and another in parallel (22.0 ohms). If the power sourc

Dafna1 [17]

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I = U / R
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3 years ago