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PtichkaEL [24]
3 years ago
15

PLEASE HELP ME (stop putting links ) Two objects m1 and m2, each with a mass of 5 kg and 6 kg separated by a distance. A third o

bject m 3= 2 kg is placed between the two. The distance between m1, and m3, is( X) and the distance between m3, from m2, is (2X+1). If the gravitational force experienced by m3, Fg= 0. What is the distance of m3, from m1, and the distance of m1, from m2.​
Physics
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

Explanation:

Newton's Gravitation Law

\displaystyle \frac{GmM}{d^2}

where G is a constant, M and M the masses e d the distance betwen masses.

\displaystyle G\frac{5\cdot2}{x^2}=G\frac{6\cdot 2}{(2x+1)^2} \quad \sqrt{6}x=(2x+1)\sqrt {5} \quad x=\frac{\sqrt{5}}{\sqrt{6}-2\sqrt{5}}

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The first law of motion is also called as law _ fill up the blanks ​
Roman55 [17]

Answer:

law of inertial

Explanation:

state that if anobject is in motion it will continue to move until some external force act on it.

5 0
3 years ago
While sitting in a moving bus you throw an apple up into the air. The apple will land back into your hand.
Neko [114]
False because you have moved after you through the apple in the air
6 0
3 years ago
If a box is pushed across a floor with a force of 130N. The frictional force acting between the box and the floor is 30N, over a
Sidana [21]
The force acting in the front direction is the 130N.
The frictional force is acting backwards          30N.

1) The net force is 130N - 30N    =  100N

2)  s  = ut + (1/2)at^2             u = 0,  Start from rest,  s = 25m t =5.

25 = 0*5  +  (1/2)* a * 5^2.

25 = 0  +  25/2  * a.

25  =    (25/2)a.      Divide 25 from both sides.

1 =  (1/2)* a.          Cross multiply.

2 = a.

a = 2 m/s^2.

3) Mass of the box
Net Force,  F = ma
                   100 =  m*2.        Divide both sides by 2.
                    
                     100/2  =  m
                       50       =  m.
                        m  = 50 kg.

4)  Final velocity ,   v = u + at.
                                   v  =  0  + 2*5 = 10 m/s.
                                  
   Kinetic Energy,  K  =  (1/2) * mv^2.
                                    =    1/2  * 50 * 10 * 10.
                                    =      2500 J.
3 0
3 years ago
In a 120-volt circuit having a resistance of 12 ohms, the power W in watts when a current I is flowing through is given by W=120
Mrac [35]

Answer:

maximum power = 300 W

Explanation:

Ohm's law: Ohm's law state that the current flowing through a metallic conductor, is directly proportional to the potential difference applied across its end. mathematically it is expressed as,

V = IR............. Equation 1

Where V = potential difference, I = current, R = Resistance of the conductor.

If the power flowing through is gives as

W = 120I - 12I² ..................... Equation 2

To get the maximum power we differentiate of equation 2  and equate to zero

dW/dt = 0

120 - 24l = 0........................... equation 3

Making I the subject of the equation,

I = 120/24 = 5 A.

Suubstituting the value of I into Equation 2

W = 120 (5) - 12(5)²

W = 600 - 300

W = 300 W.

Therefore maximum power = 300 W

5 0
4 years ago
A force of 500 N is used to slide a box across a smooth surface; the box moved 5 m in 1.2 seconds. What power is used?
Katen [24]
F = 500N
S = 5m
T = 1.2s
----------------------------------
P = ?

We can use formula P = F * V, just because it was a smooth slide we can assume that average speed was V = S/T = 5 / 1.2 = 50/12

So the final answer would be:

P = F * V = 500 * 50/12

Are you sure those are correct numbers? The answer don't look nice :D



8 0
3 years ago
Read 2 more answers
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