Answer: (-9,-1)
Step-by-step explanation:
Explanation:
1. The set of points 5 cm from the nearest point on a circle of radius 2 cm will be a circle with a radius 5 cm larger: a circle with a radius of 7 cm.
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2. The set of points 6 in from the nearest point on a line will be a cylindrical shell 12 inches in diameter centered on the line.
If AB is a line segment, then the shell will have hollow hemispherical ends of radius 6 inches about the end points.
Answer:
B. {16, 19, 20}
Step-by-step explanation:
The <em>triangle inequality</em> requires for any sides a, b, c you must have ...
a + b > c
b + c > a
c + a > b
The net result of those requirements are ...
- the sum of the two shortest sides must be greater than the longest side
- the length of the third side lies between the difference and sum of the other two sides
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If we look at the offered side length choices, we see ...
A: 8+11 = 19 . . . not > 19; not a triangle
B: 16+19 = 35 > 20; could be a triangle
C: 3+4 = 7 . . . not > 8; not a triangle
D: 5+5 = 10 . . . not > 11; not a triangle
The side lengths {16, 19, 20} could represent the sides of a triangle.
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<em>Additional comment</em>
The version of triangle inequality shown above ensures that a triangle will have non-zero area.
The alternative version of the triangle inequality uses ≥ instead of >. Triangles where a+b=c will look like a line segment--they will have zero area. Many authors disallow this case. (If it were allowed, then {8, 11, 19} would also be a "triangle.")
Answer:
HL
Step-by-step explanation:
Since both triangles are right angle triangles that means one angle is 90°. other two sides are given congruent .
that means lengths of hypotenuse and the leg of the one right angle triangle is equal to the corresponding other hypotenuse and leg of other triangle.
This fulfills the condition of HL congruency.
Answer:
Step-by-step explanation:
The foci are horizontally aligned.
horizontal ellipse:
(x-h)²/a² + (y-k)²/b² = 1
center (h,k)
vertices (h±a,k)
length of minor axis = 2b
foci (h±c,k), c² = a²-b²
Apply your data and solve for h, k, a, and b.
foci (±3√19, 6)
h = 0
k = 6
Length of minor axis = 2b = 10
b = 5
foci (h±3√19, 6)
c = 3√19
c³ = a² - b²
171 = a² - 25
a² = 196
x²/196 + (y-6)²/25 = 1
