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Lisa [10]
3 years ago
14

What is 65+78 i cant find any answer and my teacher is being a cool

Mathematics
2 answers:
igomit [66]3 years ago
6 0

Answer:

143

Step-by-step explanation:

neonofarm [45]3 years ago
4 0

Answer:143

Step-by-step explanation:

it is 143 if you add 65+78

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In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>​
Lemur [1.5K]

In both cases,

AB^2=AD^2

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

(4x+7)^2=(6x-3)^2

16x^2+56x+49=36x^2-36x+9

20x^2-92x-40=0

5x^2-23x-10=0

(5x+2)(x-5)=0\implies\boxed{x=5}

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

(4x^2-18x-10)^2=(x^2+x+4)^2

16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16

15x^4-146x^3+235x^2+352x+84=0

(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}

(again, omit the solutions that would give a negative length for either AB or AD)

7 0
3 years ago
At the Hula Factory, the assembly line produces 212 leis in a batch. The leis are packaged in boxes with 30 each. If 14 batches
nikklg [1K]

Answer:

197 leis left over

Step-by-step explanation:

14 times 212 = 2968

2968/30 = 98.93

212 times 0.93 = 197

98 packages and 197 leis left over

7 0
2 years ago
Draw the graph of g(x) = 2x + 3, if x ≥ 1 g(x) = 5, if x &gt; 1
trapecia [35]
G(x)=2x+3
x <span>≥ 1
g(x)=5
x is bigger then 1

</span>
6 0
3 years ago
In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 9
creativ13 [48]
So...we can write eqn as

40x = 50(x-1)
so. -10x=-50
so. x=5

therefore .... the distance of 40 lb will be 5 ft ...answer !!!
4 0
3 years ago
Read 2 more answers
If the range of f(x)=x+7 is {2, 10}, then the domain must be what?
KatRina [158]

f(x)=X+7 is {2, 10} then the domain must be 2 is answer

6 0
2 years ago
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