Answer:
84? Not sure but pretty sure
Step-by-step explanation:
In a straight line, the word can only be spelled on the diagonals, and there are only two diagonals in each direction that have 2 O's.
If 90° and reflex turns are allowed, then the number substantially increases.
Corner R: can only go to the adjacent diagonal O, and from there to one other O, then to any of the 3 M's, for a total of 3 paths.
2nd R from the left: can go to either of two O's, one of which is the same corner O as above. So it has the same 3 paths. The center O can go to any of 4 Os that are adjacent to an M, for a total of 10 more paths. That's 13 paths from the 2nd R.
Middle R can go the three O's on the adjacent row, so can access the three paths available from each corner O along with the 10 paths available from the center O, for a total of 16 paths.
Then paths accessible from the top row of R's are 3 +10 +16 +10 +3 = 42 paths. There are two such rows of R's so a total of 84 paths.
Answer:
80/14=5.7 OR 5 14 IN.
Step-by-step explanation:
First, let's declare a variable
x = # of students
Now, let's create an equation to model the problem.
x * 0.273 = 125
Divide both sides by 0.273
x = 457.8 = 458 students.
Note, I rounded to the nearest whole number.
Answer:
{x\ x e U and x has a negative square root} is an empty set.
Step-by-step explanation:
If x e U, x is a negative real number, and they don't have a square root (they don't have even roots). Their square roots are complex numbers, not real ones.
I think it’s A but I’m not to sure