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Pachacha [2.7K]
3 years ago
15

Factor completely 16x^3−36x

Mathematics
2 answers:
myrzilka [38]3 years ago
6 0

Answer:

4x(2x+3)(2x−3)

Step-by-step explanation:

Factor 16x3−36x

16x3−36x

=4x(2x+3)(2x−3)

Reptile [31]3 years ago
5 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em><em>⤴</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

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A batch of 40 parts contains six defects. If two parts are drawn randomly one at a time without replacement, what is the probabi
adell [148]

Answer:

a) Therefore, the probability is P=1/52.

b) Therefore, the probability is P=9/400.

Step-by-step explanation:

We know that a  batch of 40 parts contains six defects.

a) We calculate the probability that the both parts are defective, if two parts are drawn randomly one at a time without replacement.

The probability for the first is 6/40.

The probability for the second is 5/39.  

We get:

P=\frac{6}{40}\cdot \frac{5}{39}\\\\P=\frac{1}{52}

Therefore, the probability is P=1/52.

b) We calculate the probability that the both parts are defective, if two parts are drawn randomly one at a time with replacement.

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P=\frac{6}{40}\cdot \frac{6}{40}\\\\P=\frac{9}{400}

Therefore, the probability is P=9/400.

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