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yarga [219]
3 years ago
14

Where do food molecules for cecropia trees come from?

Chemistry
1 answer:
Oliga [24]3 years ago
8 0

Answer:

Central and South American forests.

Explanation: https://brainly.in/question/7540305

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Which radiation can only be stopped by thick layers of dense metal? (2 points)
AfilCa [17]
Gamma rays have the highest penetrating power so it can only be stopped by thick layers of dense metal. :)
5 0
3 years ago
Read 2 more answers
Which of the following particles combine to form molecules?
solniwko [45]

Answer: i think its protons and electrons but it also might just be atoms because protons and electrons  make atoms when there are also neutrons

Explanation:

7 0
3 years ago
2. How much heat is released when 432g of water cools down from 710C to 180C?
nadya68 [22]
The heat released by the water when it cools down by a temperature difference AT

is Q = mC,AT

where

m=432 g is the mass of the water

C, = 4.18J/gºC

is the specific heat capacity of water

AT = 71°C -18°C = 530

is the decrease of temperature of the water

Plugging the numbers into the equation, we find

Q = (4329)(4.18J/9°C)(53°C) = 9.57. 104J

and this is the amount of heat released by the water.
7 0
3 years ago
The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium
Ksenya-84 [330]

Answer:

The concentration is C = 1.11 mol/L

Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

Generally absorbance is mathematically represented as

        A =  \epsilon*  C * l

where \epsilon is the molar absorptivity of  FeSCN2  with a value \epsilon  =  7.0*10^3 L/cm/mol

 and  C is the equilibrium concentration of FeSCN2

So  

       C = \frac{A}{\epsilon *  l  }

substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

         C = 1.11 mol/L

5 0
3 years ago
If 0.0106 g of a gas dissolves in 0.792 L of water at 0.321 atm, what quantity of this gas (in grams) will dissolve at 5.73 atm?
Alex73 [517]

Answer:

0.189 g.

Explanation:

  • This problem is an application on <em>Henry's law.</em>
  • Henry's law states that the solubility of a gas in a liquid is directly proportional to its partial pressure of the gas above the liquid.
  • Solubility of the gas ∝ partial pressure
  • If we have different solubility at different pressures, we can express Henry's law as:

<em>S₁/P₁ = S₂/P₂,</em>

S₁ = 0.0106/0.792 = 0.0134 g/L and P₁ = 0.321 atm

S₂ = ??? g/L and P₂ = 5.73 atm

  • So, The solubility of the gas at 5.73 atm (S₂) = S₁.P₂/P₁ = (0.0134 g/L x 5.73 atm) / (0.321 atm) = 0.239 g/L.

<em>The quantity in (g) = S₂ x V = (0.239 g/L)(0.792 L) = 0.189 g.</em>

<em></em>

8 0
3 years ago
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