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vazorg [7]
3 years ago
15

Match each term with its definition.

Chemistry
1 answer:
padilas [110]3 years ago
4 0

Answer:

The position of an equilibrium always shifts in such a direction as to relieve a stress applied to the system -Le Chåtelier's principle

A molecule that donates a proton when it encounters a proton acceptor.- Bronsted-Lowry acid

Occurs when a reaction involving an acid and its conjugate base is combined with a second reaction involving a base and its conjugate acid.- Neutralization

It ionizes completely when dissolved in water.- Strong acid

The shift in the position of equilibrium caused by the addition of a participating ion.- Common ion effect

It only partially ionizes when dissolved in water.- Weak electrolyte

It is capable of acting as either an acid or a base depending upon the solute- Amphoteric solvent

The act of self-ionization of a solvent to produce both a conjugate acid and a conjugate base.- Auto-protolysis

A chemical species that bears both positive and negative charges.- Zwitterion

Explanation:

In the answer box we have various chemical terminologies and their definitions. In answering the question, you must carefully read through each definition, then check what option best matches that definition from the options provided.

Each definition applies only to one terminology as you can see in the answer above.

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2. The approximate concentration of hydrochloric acid, HCl, in the stomach (stomach
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Answer:

a) 0.714g of bicarbonate of soda are required.

b) 0.221g of Al(OH)₃ are required

Explanation:

The reactions of HCl with bicarbonate of soda and aluminium hydroxide are:

HCl + NaHCO₃ → H₂O + NaCl + CO₂

3 HCl + Al(OH)₃ → 3H₂O + AlCl₃

The moles of HCl that we need neutralize are:

50mL = 0.050L * (0.17mol / L) = 0.0085 moles HCl

To solve these problem we need to find the moles of the antacid using the chemical reaction and its mass using its molar mass;

<em>a) </em><em>Moles NaHCO₃ = Moles HCl = 0.0085 moles </em>

The mass is -Molar mass NaHCO₃: -84g/mol-

0.0085 moles * (84g / mol) = 0.714g of bicarbonate of soda are required

b) 0.0085 moles HCl * (1mol Al(OH)₃ / 3mol HCl) = 2.83x10⁻³ moles Al(OH)₃

The mass is -Molar mass: 78g/mol-:

2.83x10⁻³ moles Al(OH)₃ * (78g/mol) =

<h3>0.221g of Al(OH)₃ are required</h3>
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