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topjm [15]
3 years ago
11

An experimenter performs a RICS experiment using a mixture (mixture 1:1 of monomers and tetramers, with a total concentration of

2nM. The instrument has a pixel size of 50nm, the total number of pixels in a line is 256 and there are 256 lines. The pixel dwell time is 2microseconds. Assume no retracing time. The beam wait in radial direction is 300 nm and in the axial direction is 5 times larger. What is the measured amplitude of the RICS correlation function
Chemistry
1 answer:
ICE Princess25 [194]3 years ago
4 0

Answer:

Raster Image Correlation Spectroscopy (RICS) is a novel new technique for measuring molecular dynamics and confocal fluorescence imaging concentrations. RICS technique extracts information on molecular dynamics and concentrations of live cell images taken in commercial confocal systems

Explanation:

RICS analysis must be performed on images acquired through raster scanning. Laser scanning microscopes generate images by measuring the fluorescence intensity in one area of ​​a pixel at a time (a 'pixel' in this context does not have the same definition as a pixel in computer graphics, but refers to a measurement of localized intensity). The value of a pixel is obtained by illuminating a region of the sample with the focal volume of a laser beam and measuring the intensity of the fluorescence emitted. The laser beam moves to a new location and a new pixel is recorded. Each pixel can be considered to correspond to a region of the sample, with its width (called pixel size) defined by the distance the beam moves between measurements. This means that the size of a pixel is separate and independent from the size of the focal volume of the laser beam.

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If the pressure on a 1.04 L sample of gas is doubled at constant temperature, please compute the new volume of gas: __
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Answer:

0.52 L.

Explanation:

Let P be the initial pressure.

From the question given above, the following data were obtained:

Initial pressure (P1) = P

Initial volume (V1) = 1.04 L

Final pressure (P2) = double the initial pressure = 2P

Final volume (V2) =?

The new volume (V2) of the gas can be obtained by using the the Boyle's law equation as shown below:

P1V1 = P2V2

P × 1.04 = 2P × V2

1.04P = 2P × V2

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V2 = 1.04P /2P

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What are two main purposes for using repetition when conducting experiments <br> irements
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3 years ago
Read 2 more answers
What is the concentration of each ion in a solution that is prepared by dissolving 5.00 g of ammonium chloride in enough water t
sukhopar [10]

The concentration of each ion in the solution of ammonium chloride is:

  • NH₄⁺ = 0.1886 M
  • Cl⁻ = 0.1886 M

To solve this problem, the formulas and the procedures that we have to use are:

  • M = n(solute)/v(solution) L
  • n = m / MW
  • MW= ∑ AWT

Where:

  • M= molarity
  • n = moles
  • m = mass
  • v = volume
  • MW = molecular weight
  • AWT = atomic weight

Information about the problem:

  • m(NH₄Cl) = 5 g
  • v(solution) = 500 ml
  • AWT (N)= 14 g/mol
  • AWT (H)= 1 g/mol
  • AWT (Cl) = 35 g/mol

Converting the volume units from (ml) to (L) we have:

v(solution) = 500 ml * (1 L/1000 ml)

v(solution) = 0,50 L

We calculate the moles of the NH₄Cl from the MW:

MW = ∑ AWT

MW (NH₄Cl)= AWT (N) + AWT (H)*4 + AWT (Cl)

MW (NH₄Cl)= 14 g/mol +( 1 g/mol * 4) + 35 g/mol

MW (NH₄Cl)= 14 g/mol + 4 g/mol + 35 g/mol

MW (NH₄Cl)= 53 g/mol

Having the MW we calculate the moles of NH₄Cl:

n(NH₄Cl) = m(NH₄Cl) / MW(NH₄Cl)

n(NH₄Cl) = m(H2SO4) / MW (H2SO4)

n(NH₄Cl) =  5 g / 53 g/mol

n(NH₄Cl) = 0.0943 mol

Applying the molarity formula, we get:

M(NH₄Cl) = n(NH₄Cl)/v(solution) L

M(NH₄Cl) = 0.0943 mol / 0,50 L

M(NH₄Cl) = 0.1886 M

There are 0.1886 moles of NH₄Cl per liter of solution.

Let's recognize that 1 mol NH₄Cl contains:

  • 1 mol NH₄⁺
  • 1 mol Cl⁻

The concentration of each ion is thus:

(1)*(0.1886 M) = 0.1886 M NH₄⁺

(1)*(0.1886 M) = 0.1886 M Cl⁻

<h3>What is a solution?</h3>

In chemistry a solution is known as a homogeneous mixture of two or more components called:

  • Solvent
  • Solute

Learn more about chemical solution at: brainly.com/question/13182946 and brainly.com/question/25326161

#SPJ4

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2 years ago
The strongest intermolecular interactions between hydrogen fluoride (hf) molecules arise from
aliya0001 [1]
Answer:
            <span>The strongest intermolecular interactions between hydrogen fluoride (hf) molecules arise from Hydrogen Bonding.

Explanation:
                   Hydrogen Bond interactions are considered the strongest intermolecular interactions among molecules. These interactions are found between Hydrogen atom of one molecule bonded to most electronegative atoms (i.e F, O, N) and the most electronegative atoms of neighbor molecule.
                  In case of HF, fluorine has the greatest electronegativity of 4, so the hydrogen bonded to Fluorine becomes partial positive and makes Hydrogen bond with Fluorine atom of </span>neighbor HF molecule.<span />
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