A reaction that produces 14.2 grams of a product and the theoretical yield of that product is 17.1 grams is true for the following statements :
The percent yield of the product is 83.0%
The actual yield of the product is 14.2 grams.
<h3>Percentage Yield:</h3>
Percent yield is the percent ratio of actual yield to the theoretical yield.
Mathematically,
percent yield = actual yield / theoretical yield x 100%
actual yield = 14.2 grams
theoretical yield = 17.1 grams
percentage yield = 14.2 / 17.1 × 100%
percentage yield = 83.0409356725 %
percentage yield = 83.0 %
Therefore,
The percent yield of the product is 83.0%
The actual yield of the product is 14.2 grams.
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Answer:
Explanation:
molar mass of BaCl2 = 208.23
mol of BaCl2 = 8/208.22
mol of BaCl2 = 0.03841905
Molarity = 0.03841905/0.450
Molarity = 0.085 M
Answer:
A) mass divided by volume
Explanation:
The rate constant is mathematically given as
K2=2.67sec^{-1}
<h3>What is the Arrhenius equation?</h3>
The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:
Therefore
KT1= 0.0110^{-1}
T1= 21+273.15
T1= 294.15K
T2= 200
T2=200+273.15
T2= 473.15K
Ea= 35.5 Kj/Mol
Hence, in j/mol R Ea is
Ea=35.5*1000 j/mol R
K2/0.0110 =e^(5.492)
K2/0.0110 =242.74
K2= 242.74*0.0110
K2=2.67sec^{-1}
In conclusion, rate constant
K2=2.67sec^{-1}
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Answer:
2Ag(s) + Cu^2+(aq) ----------> 2Ag^+(aq) + Cu(s)
Explanation:
Ag(s)/Ag^+ (aq) is the anode as shown while Cu^2+(aq)/Cu^2(s) is the cathode.
E°cell= E°cathode -E°anode= 0.34 -0.80= -0.5V
The cell is not spontaneous as written because E°cell is negative. This implies that the electrodes of the cell must be interchanged to make the cell spontaneous.
