Im not too sure about this one could i get some help with it?
1 answer:
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Answer:
The upper limit of a 95% confidence interval for the population mean would equal 83.805.
Step-by-step explanation:
The standard deviation is the square root of the variance. Since the variance is 25, the sample's standard deviation is 5.
We have the sample standard deviation, not the population, so we use the t-distribution to solve this question.
T interval:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 15 - 1 = 14
Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of 0.95(). So we have T = 1.761
The margin of error is:
M = T*s = 1.761*5 = 8.805.
The upper end of the interval is the sample mean added to M. So it is 75 + 8.805 = 83.805.
The upper limit of a 95% confidence interval for the population mean would equal 83.805.
Answer:
The correct choice is:
-2 to the 4th power is positive 16.
Option C is correct.
Step-by-step explanation:
We need to find mistake make in work below:
The mistake here is when we have even power, the negative sign gets positive i.e if m is even
so, in our case it would be:
The correct choice is:
-2 to the 4th power is positive 16.
Option C is correct.
I hope this helps with you
