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elena-s [515]
3 years ago
13

It requires 0.30 kJ of work to fully drive a stake into the ground. If the average resistive force on the stake by the ground is

828 N, how long is the stake?
Physics
1 answer:
LenaWriter [7]3 years ago
6 0

Answer:

Length of the stake will be 0.3623 m

Explanation:

We have given energy required to fully drive a stake into ground = 0.30 KJ = 300 J

Average resistive force acting on the floor is equal to F = 828 N

We have to find the length of the stake

We know that work done is given by

W = Fd, here W is work done , F is average force and d is the length of the stake

So 300 = 828×d

d = 0.3623 m

So length of the stake will be 0.3623 m

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