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Orlov [11]
4 years ago
8

A researcher is studying traffic patterns at an intersection before an upcoming construction project. As part of this investigat

ion, the researcher writes a scientific question, develops a procedure to observe traffic specifically at this intersection, and draws a conclusion. Which type of investigation is the researcher conducting? descriptive comparative experimental procedural
Physics
2 answers:
Anna [14]4 years ago
7 0

Answer:

Procedural is the answer

hope this helps

Artemon [7]4 years ago
4 0
Answer: Procedural

Explanation: It states in the question that he developed a procedure! If this was something you have heard before, this is definitely the answer. Goodluck! ☺️
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I NEED HELP PLEASE, THANKS! :) Compare and contrast electric potential energy and electric potential difference?
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Workdone in bringing a unit positive charge from low potential to higher potential against the electric field is electric potential energy.

Electric potential difference is yhe difference of potential energy at the terminals of battery or conductor eire attached to the battery.

Explanation:

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What kind of reaction (endothermic or exothermic)
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Exothermic is the right kind of reaction.
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What is a common cause of insomnia? (2 points)
Verizon [17]

Answer:

stress

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3 years ago
Two particles with charges of 2nC and 5nC are separated by a distance of 3m. The charge 2nC is placed on the left. Find the forc
Vanyuwa [196]

Answer:

1\cdot 10^{-8} N to the left

Explanation:

The magnitude of the electrostatic force between two charges is given by the following equation:

F=k\frac{q_1 q_2}{r^2}

where:

k=9\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the magnitude of the two charges

r is the distance between the two charges

Moreover, the force is:

- Attractive if the charges have opposite sign

- Repulsive if the charges have same sign

In this problem, we have:

q_1=2nC=2\cdot 10^{-9}C is the magnitude of charge 1

q_2=5nC =5\cdot 10^{-9}C is the magnitude of charge 2

r = 3 m is the distance between the two charges

Substituting, we find the force on both charges:

F=\frac{(9\cdot 10^9)(5\cdot 10^{-9})(2\cdot 10^{-9}}{3^2}=1\cdot 10^{-8} N

Here, the two charges are both positive, so the force is repulsive; since the 2 nC charge is on the left, this means that the force on this charge is to the left (away from the 5 nC charge).

5 0
3 years ago
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