Answer:
884Hz
Explanation:
Beats is the absolute difference between two frequencies therefore
Beats = f1-f2
4=f1-880
F1=880+4
F1=884Hz
Answer:
True
Explanation:
This is because to know how someone behaves, they have to perform a particular action.
Answer:
5080.86m
Explanation:
We will divide the problem in parts 1 and 2, and write the equation of accelerated motion with those numbers, taking the upwards direction as positive. For the first part, we have:
![y_1=y_{01}+v_{01}t+\frac{a_1t^2}{2}](https://tex.z-dn.net/?f=y_1%3Dy_%7B01%7D%2Bv_%7B01%7Dt%2B%5Cfrac%7Ba_1t%5E2%7D%7B2%7D)
![v_1=v_{01}+a_1t](https://tex.z-dn.net/?f=v_1%3Dv_%7B01%7D%2Ba_1t)
We must consider that it's launched from the ground (
) and from rest (
), with an upwards acceleration
that lasts a time t=9.7s.
We calculate then the height achieved in part 1:
![y_1=(0m)+(0m/s)t+\frac{(28m/s^2)(9.7s)^2}{2}=1317.26m](https://tex.z-dn.net/?f=y_1%3D%280m%29%2B%280m%2Fs%29t%2B%5Cfrac%7B%2828m%2Fs%5E2%29%289.7s%29%5E2%7D%7B2%7D%3D1317.26m)
And the velocity achieved in part 1:
![v_1=(0m/s)+(28m/s^2)(9.7s)=271.6m/s](https://tex.z-dn.net/?f=v_1%3D%280m%2Fs%29%2B%2828m%2Fs%5E2%29%289.7s%29%3D271.6m%2Fs)
We do the same for part 2, but now we must consider that the initial height is the one achieved in part 1 (
) and its initial velocity is the one achieved in part 1 (
), now in free fall, which means with a downwards acceleration
. For the data we have it's faster to use the formula
, where d will be the displacement, or difference between maximum height and starting height of part 2, and the final velocity at maximum height we know must be 0m/s, so we have:
![v_{02}^2+2a_2(y_2-y_{02})=v_2^2=0m/s](https://tex.z-dn.net/?f=v_%7B02%7D%5E2%2B2a_2%28y_2-y_%7B02%7D%29%3Dv_2%5E2%3D0m%2Fs)
Then, to get
, we do:
![2a_2(y_2-y_{02})=-v_{02}^2](https://tex.z-dn.net/?f=2a_2%28y_2-y_%7B02%7D%29%3D-v_%7B02%7D%5E2)
![y_2-y_{02}=-\frac{v_{02}^2}{2a_2}](https://tex.z-dn.net/?f=y_2-y_%7B02%7D%3D-%5Cfrac%7Bv_%7B02%7D%5E2%7D%7B2a_2%7D)
![y_2=y_{02}-\frac{v_{02}^2}{2a_2}](https://tex.z-dn.net/?f=y_2%3Dy_%7B02%7D-%5Cfrac%7Bv_%7B02%7D%5E2%7D%7B2a_2%7D)
And we substitute the values:
![y_2=y_{02}-\frac{v_{02}^2}{2a_2}=(1317.26m)-\frac{(271.6m/s)^2}{2(-9.8m/s^2)}=5080.86m](https://tex.z-dn.net/?f=y_2%3Dy_%7B02%7D-%5Cfrac%7Bv_%7B02%7D%5E2%7D%7B2a_2%7D%3D%281317.26m%29-%5Cfrac%7B%28271.6m%2Fs%29%5E2%7D%7B2%28-9.8m%2Fs%5E2%29%7D%3D5080.86m)
Answer:
1.846....hours
Explanation:
since if we divide 12 km or just 12 by 6.5 we will get this number meaning that this is how long it would take someone
Answer:
48
Explanation:
you basically divide 1200 into 25