The square root of 80 is: 8.944
Answer:
Option (D)
Explanation:
Terrestrial planets refers to those four planets that are nearest to the sun and that lies within the asteroid belt. These planets are mainly composed of rocks or other metal objects that have a hard and resistant surface on it. They have a metal core that is molten (liquid) in nature, and atmosphere is relatively less dense, and also various geological features are present on it like the crater, volcanoes which can be observed with the help of satellites. The average densities of these planets is about four times the density of water. For example, the density of water is 1 g/cm³, whereas the density of earth is 5.5 g/cm³.
Thus, the correct answer is option (D).
Answer:
Connect multiple hosts: Normally, a switch provides a large number of ports for cable connections, allowing for star topology routing. It is usually used to connect multiple PCs to the network.
Forwards a message to a specific host: Like a bridge, a switch uses the same forwarding or filtering logic on each port. When any host on the network or a switch sends a message to another host on the same network or the same switch, the switch receives and decodes the frames to read the physical (MAC) address portion of the message.
Manage traffic: A switch in networking can manage traffic either coming into or exiting the network and can connect devices like computers and access points with ease.
Keep electrical signal undistorted: When a switch forwards a frame, it regenerates an undistorted square electrical signal.
Increase LAN bandwidth: A switch divides a LAN into multiple collision domains with independent broadband, thus greatly increasing the bandwidth of the LAN.
Explanation:
The energy stored in a capacitor is given by:
![U= \frac{1}{2}CV^2](https://tex.z-dn.net/?f=U%3D%20%5Cfrac%7B1%7D%7B2%7DCV%5E2%20)
where
U is the energy
C is the capacitance
V is the potential difference
The capacitor in this problem has capacitance
![C=3.0 \mu F = 3.0 \cdot 10^{-6} F](https://tex.z-dn.net/?f=C%3D3.0%20%5Cmu%20F%20%3D%203.0%20%5Ccdot%2010%5E%7B-6%7D%20F)
So if we re-arrange the previous equation, we can calculate the potential V that should be applied to the capacitor to store U=1.0 J of energy on it: