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kati45 [8]
4 years ago
11

What is the energy Q released when 131 53Idecays and 131 54Xe is formed? The atomic mass of 131 53I is 130.906118 u and the atom

ic mass of 131 54Xe is 130.90508 u.
Physics
1 answer:
DanielleElmas [232]4 years ago
5 0

Answer:0.967meV

Explanation:

-Find the difference in u, so 130.906118-130.90508= 0.001038u

- convert to meV

1 u = 931.494meV

multiply 0.001038 by 931.494

=0.001038 X 931.494

0.967 meV

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a car is moving with a constant speed of 20 meters per second.What total distance does the car travel in 2 minutes
N76 [4]
There are 120 seconds in two minutes, so to find the answer, you multiply 20 x 120 to get 2400 meters.
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3 years ago
what is the potential difference across the headlight bulbs when the starter motor is operated, requiring an additional 39 a fro
frosja888 [35]

The starter motor's potential difference across the headlight bulbs is 38.45V, requiring an additional 39 a from the battery. Voltage, also known as potential difference.

It is sometimes described as the amount of work needed to move a test charge between two sites, expressed as a unit of charge. Volt is the potential difference's SI unit (V). We only take into account the charge between the locations P and Q when current moves between them in an electric circuit. Electric potential difference between two sites is referred to as voltage, also known as electric pressure, electric tension, or (electric) potential difference. an electric field that is static.

Vh = I*Rn

Vh = 39/5.476*5.40v

Vh = 38.45v

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brainly.com/question/13521443

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5 0
1 year ago
Consider two identical objects released from rest high above the surface of Earth. (Neglect air resistance for this question.)
Nadusha1986 [10]

The question is missing its alternatives. Here is the complete question.

Consider two identical objects released from rest high above the surface of Earth. In Case 1, the object is released from a height above the surface of Earth equal to 1 Earth radius, and we measure its kinetic energy just before it hits the Earth to be K1. In Case 2, the obejct is released from a height above the surface of Earth equal to 2 Earth radii and its kinetic energy just before it hits is K2.

1. Compare the kinetic energy of the two objects just before they hit the surface of the earth.

a) K2 = 2K1; b) K2 = 4K; c) K2 = (4/3)K1; d) K2 = (3/2)K1;

Answer: C) K2 = (4/3)K1

Explanation: As it is related to the gravity of the Earth, the potencial energy is: U(r)= - \frac{G.Me.m}{r} + U₀

In this case, U₀=0, G is the universal gravitational constant, Me is the mass of Earth, m is the mass of the object and r is the distance between the center of the Earth and the object.

The potencial energy of an object of mass m on the surface of the Earth is:

Usurface = - \frac{G.Me.m}{Re}

The potencial energy of the object in Case 1 is

U1 = - \frac{G.Me.m}{2Re}

For the Case 2:

U2 = - \frac{G.Me.m}{3Re}

The potencial change in Case 1:

ΔU1 = - G.Me.m.(\frac{1}{Re}-\frac{1}{2Re}) = - \frac{1}{2}\frac{G.Me.m}{Re}

For Case 2:

ΔU2 = - G.Me.m(\frac{1}{Re}-\frac{1}{3Re}) = - \frac{2}{3}\frac{G.Me.m}{Re}

Comparing ΔK1 and ΔK2 equals comparing ΔU1 and ΔU2:

Δ\frac{U2}{U1} = (-2/3)(-1/2) = 4/3

So, comparing kinetic energies, K2 is 4/3 of K1.

5 0
4 years ago
A train is traveling at 30.0 m/sm/s relative to the ground in still air. The frequency of the note emitted by the train whistle
Zigmanuir [339]

Answer

given,

speed of sound = 344 m/s

speed of train = 30 m/s

frequency emitted by the train = 262 Hz

   Doppler's effect

    f_L = \dfrac{v + v_L}{v + v_s}\ f_S

f_L is the frequency of listener

f_S is the frequency of the source of the sound

v is the speed of the sound

v_L is the speed of listener.

v_S is the speed of the source

a) Speed of the passenger in another train , v = 18 m/s

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   v_L is positive as the listener is moving forward.

    v_S is negative at the source is moving toward the listener.

      f_L = \dfrac{344 + 18}{344 - 30}\times 262

     f_L = 302\ Hz

b) Speed of the passenger in another train , v = 18 m/s

   another train is moving in opposite direction and receding

    v_L is negative as the listener is moving away from source.

    v_S is positive at the source is moving away the listener.

      f_L = \dfrac{344 - 18}{344 + 30}\times 262

     f_L = 228.37\ Hz

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GREYUIT [131]

Answer:

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Explanation:

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