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Calculate the compound amount. Use the compound amount formula and a calculator. (Round your answer to two decimal places.) P =

Julli [10]

Answer:

The compound amount is $303.03 .

Explanation:

Formula for compound interest:

$A=P\times (1+\frac{R}{n})^{tn})$

Principle amount = $1100

Rate of the interest compounded semiannually :

= R = 9% = 0.09

Number of times interest compounded, n = $\frac{12}{6}=2$

(semi means two times in a year)

Time period = T = 14

$A=\$1100\times (1+\frac{0.09}{2})^{2\times 14}=\$303.0310\approx \$303.03$

The compound amount is $303.03 .

5 0

4 years ago

What volume of O2(

irakobra [83]

Answer is: volume of oxygen is 4.63 liters.
Balanced chemical reaction: 2C + O₂ → 2CO.
m(C) = 4.50 g.
n(C) = m(C) ÷ M(C).
n(C) = 4.50 g ÷ 12 g/mol.
n(C) = 0.375 mol.
From chemical reaction: n(C) : n(O₂) = 2 : 1.
n(O₂) = 0.1875 mol.
T = 48°C = 321.15 K.
p = 810 mmHg ÷ 760 mmHg/atm= 1.066 atm.
R = 0.08206 L·atm/mol·K.
Ideal gas law: p·V = n·R·T.
V(O₂) = n·R·T / p.
V(O₂) = 0.1875 mol · 0.08206 L·atm/mol·K · 321.15 K / 1.066 atm.
V(O₂) = 4.63 L.

4 0

3 years ago

Maria said that you can blu always separate a mixture by filtration. Is she correct?

Olegator [25]

Yes because it’s true

8 0

3 years ago

Read 2 more answers

How far will a car go that is moving at 10 m/s in 1 hour

Airida [17]

Answer:

36,000 miles in one hour.

Explanation:

Because there are 60 seconds in a minute and 60 minutes in an hour so to find out how many seconds are in an hour you multipy 60x60 to get 3600. Then to find out how many miles in the 3600 seconds you multiply 10 x 3600 to get 36000.

4 0

3 years ago

Pentane is a small liquid hydrocarbon, between propane and gasoline in size at C5H12. The density of pentane is 0.626 g/mL and i

Goshia [24]

Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and $3.073\times 10^4kJ/L$ respectively.

Explanation :

Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).

As we are given that:

$\Delta H^o_{comb}=-3535kJ/mol$

Fuel value = $\frac{\Delta H^o_{comb}}{\text{Molar mass of pentane}}$

Molar mass of pentane = 72 g/mol

Fuel value = $\frac{3535kJ/mol}{72g/mol}$

Fuel value = 49.09 kJ/g

Now we have to calculate the fuel density of pentane.

Fuel density = Fuel value × Density

Fuel density = (49.09 kJ/g) × (0.626g/mL)

Fuel density = 30.73 kJ/mL = $3.073\times 10^4kJ/L$

Thus, the fuel density of pentane is $3.073\times 10^4kJ/L$

4 0

4 years ago

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