Answer:- 171 g
Solution:- It asks to calculate the grams of sucrose required to make 1 L of 0.5 Molar solution of it.
We know that molarity is moles of solute per liter of solution.
If molarity and volume is given then, moles of solute is molarity times volume in liters.
moles of solute = molarity* liters of solution
moles of solute = 0.5*1 = 0.5 moles
To convert the moles to grams we multiply the moles by molar mass.
Molar mass of sucrose = 12(12) + 22(1) + 11(16)
= 144 + 22 + 176
= 342 grams per mol
grams of sucrose required = moles * molar mass
grams of sucrose required = 0.5*342 = 171 g
So, 171 g of sucrose are required to make 1 L of 0.5 molar solution.
When two gases of a chemical reaction are at the same temperature, pressure and molar volume, then the stoichiometric ratio of the gases would be 1 is to 1. Molar volume is the volume of the gas per mole of the gas. Having the same conditions for both gases would mean that they are present with the same number of moles.
Answer:
divergent
Explanation:
I believe it is divergent.
Answer:
299.14 K or 26°C
Explanation:
The ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas.
The ideal gas law is often written as
PV = nRT
where P ,V and T are the pressure, volume and absolute temperature;
n is the number of moles of gas and R is the ideal gas constant.
n=1.10 x 10^5 mol
V= 2.70 x 10^6 L
P= 1.00 atm= 101.325 kPa
R= 8.314 kPa*L/ mol*K
when the formula is rearranged, T=PV/ nR
T = (101.325kPa * 2.70 x 10^6 L)/ (1.10 x 10^5 mol * 8.314 kPa*L/ mol*K)
T = 299.1421917 K
or
T = 299.14 - 273.15 = 25.99 = 26°C
