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blagie [28]
3 years ago
6

The weights of Sarus crane chicks and hooded crane chicks H (both in grams) during the 10 days following hatching can be modeled

by the functions S = –0.122t3 + 3.49t2 – 14.6t + 136 H = –0.115t3 + 3.71t2 – 20.6t + 124 where t is the number of days after hatching. According to the models, what is the difference in weight between 5-day-old Sarus crane chicks and hooded crane chicks? Round your answer to the nearest thousandth, if necessary.
Mathematics
1 answer:
Katarina [22]3 years ago
6 0

Answer:

  • 35.875 grams

Step-by-step explanation:

Given

<u>Functions:</u>

  • S(t) = –0.122t³ + 3.49t² – 14.6t + 136
  • H(t) = –0.115t³ + 3.71t² – 20.6t + 124  

<u>Finding the difference between S(5) and H(5)</u>

  • S(5) - H(5) =
  • –0.122t³ + 3.49t² – 14.6t + 136  - (–0.115t³ + 3.71t² – 20.6t + 124) =
  • (-0.122 + 0.115)*5³ + (3.49 -3.7)*5² - (14.6 -20.6)*5 + 136 - 124 = 35.875

Answer is 35.875 grams

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(6 8/25 ÷(−1)−(−0.8)·(−0.1))÷(−0.25÷1.25−1 3/5 ÷(−5 1/3 ))
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Step-by-step explanation:

Given expression

\left(6 \dfrac{8}{25}\div (-1)-(-0.8)\cdot (-0.1)\right)\div\left (-0.25\div 1.25-1 \dfrac{3}{5} \div\left(-5 \dfrac{1}{3} \right)\right)

Perform all multiplications and divisions:

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Now subtract results in brackets:

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