1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kazeer [188]
3 years ago
12

U-235 releases an average of 2.5 neutrons per fission, while Pu-239 releases an average of 2.7 neutrons per fission. Which of th

ese elements might you therefore expect to have the smaller critical mass
Physics
1 answer:
Komok [63]3 years ago
5 0

Answer:

Pu - 239 have the smaller critical mass.

Explanation:

Critical mass is the smallest amount of certain element of mass that is needed to achieve a nuclear chain reaction early . Since Pu - 239 releases an average of 2.7 neutrons per fission as compared to U - 235 that releases 2.5 neutrons per fission. So, Pu - 239 has smaller critical mass, because Pu - 239 has a higher probability for fission and produces a large no. of neutrons per fission event. Infact of all the basic nuclear fuels, Pu - 239 has smallest critical mass. Critical mass depends on the nuclear properties of elements undergoing fission reaction. Hence, as Pu - 239 produces large no. of neutrons per fission than U - 235 and Pu - 239 has smaller critical mass.

You might be interested in
Using information about natural laws, explain why some car crashes produce minor injuries and others produce catastrophic injuri
Ludmilka [50]
It all has to do with what's going on around us. The speed of the vehicles, the type of vehicle, the safety factors, seatbelts, where you are in the car, what was the force of the impact, etc; Every accident has different factors playing into them in order to lead to said injuries 
3 0
2 years ago
Read 2 more answers
A young man and woman are sitting on opposite sides of a park bench (1m). If the young man has a mass of 70kg and the woman has
ZanzabumX [31]

Answer:

130N

Explanation:

F<em>=</em><em>(</em><em>M1+</em><em>M</em><em>2</em><em>)</em><em>V</em>

<em>F=</em><em> </em><em>(</em><em>7</em><em>0</em><em>+</em><em>6</em><em>0</em><em>)</em><em>*</em><em>1</em>

<em>F=</em><em>1</em><em>3</em><em>0</em><em>*</em><em>1</em>

<em>F=</em><em>1</em><em>3</em><em>0</em><em>N</em><em>/</em><em>/</em>

6 0
2 years ago
Two boxes on opposite ends of a massless board that is 3.0 m long. The board is supported in the middle by a fulcrum. The box on
rosijanka [135]

Answer:

b. 1.1 m

Explanation:

It is given that the total distance between the masses is equal to the length of the board, which is 3 m. Therefore,

s_{1} + s_{2} = 3\ m\\\\s_{2} = 3\ m - s_{1}\ --------- eqn(1)

where,

s₁ = distance of fulcrum from left mass

s₂ = distance of fulcrum from right mass

In order to achieve balance, the torque due to both masses must be equal:

T_{1} = T_{2}\\m_{1}s_{1} = m_{2}s_{2}\\(25\ kg)(s_{1}) = (15\ kg)(s_{2})\\\\\frac{15\ kg}{25\ kg}(s_{2}) = s_{1}\\\\using\ eqn(1):\\(0.6)(3\ m - s_{1}) = s_{1}\\1.8\ m = 1.6\ s_{1}\\s_{1} = \frac{1.8\ m}{1.6}

s₁ = 1.1 m

Hence, the correct option is:

<u>b. 1.1 m</u>

4 0
2 years ago
Write equations for both the electric and magnetic fields for an electromagnetic wave in the red part of the visible spectrum th
Strike441 [17]

Answer:

E=3.5(8.98*10^{6}x-2.69*10^{15}t)

B=1.17*10^{-8}(8.98*10^{6}x-2.69*10^{15}t)

Explanation:

The electric field equation of a electromagnetic wave is given by:

E=E_{max}(kx-\omega t) (1)

  • E(max) is the maximun value of E, it means the amplitude of the wave.
  • k is the wave number
  • ω is the angular frequency

We know that the wave length is λ = 700 nm and the peak electric field magnitude of 3.5 V/m, this value is correspond a E(max).

By definition:

k=\frac{2\pi}{\lambda}            

k=8.98*10^{6} [rad/m]      

And the relation between λ and f is:                

c=\lambda f

f=\frac{c}{\lambda}

f=\frac{3*10^{8}}{700*10^{-9}}

f=4.28*10^{14}

The angular frequency equation is:

\omega=2\pi f

\omega=2\pi*4.28*10^{14}

\omega=2.69*10^{15} [rad/s]

Therefore, the E equation, suing (1), will be:

E=3.5(8.98*10^{6}x-2.69*10^{15}t) (2)

For the magnetic field we have the next equation:

B=B_{max}(kx-\omega t) (3)

It is the same as E. Here we just need to find B(max).

We can use this equation:

E_{max}=cB_{max}

B_{max}=\frac{E_{max}}{c}=\frac{3.5}{3*10^{8}}

B_{max}=1.17*10^{-8}T

Putting this in (3), finally we will have:

B=1.17*10^{-8}(8.98*10^{6}x-2.69*10^{15}t) (4)

I hope it helps you!

8 0
3 years ago
You throw a ball vertically upward, and as it leaves your hand, its speed is 10.0 m/s.
8090 [49]
The answer is A bc I did the quiz and I got it right
5 0
3 years ago
Other questions:
  • X-rays can be dangerous. Please select the best answer from the choices provided T F
    10·2 answers
  • What is the path of an electron moving at 4 000 m/s perpendicular to a magnetic field of 1.5 T? (me = 9.11 x 10^-31kg)
    13·1 answer
  • A 90.0-kg fullback running east with a speed of 5.00 m/s is tackled by a 95.0-kg opponent running north with a speed of 3.00 m/s
    14·1 answer
  • The electric potential V in the space between two flat parallel plates 1 and 2 is given (in volts) by V = 2200x2, where x (in me
    15·1 answer
  • Can someone please help me with this problem
    11·1 answer
  • The temperature in a room is 56 degrees Celsius, what would the velocity of sound wave be as temperature?
    11·1 answer
  • Which system of equations and solution can be used to represent the radius if the mass of the cylinder is 11,000 grams
    7·1 answer
  • Which type of electricity moves along part way to turn on light ​
    10·1 answer
  • Please answer soon
    8·1 answer
  • General kinematics problem.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!