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Aleonysh [2.5K]
3 years ago
13

How much force does it take to accelerate a 50.8 kg person at 3.50 m/s^2?

Physics
1 answer:
Vikki [24]3 years ago
8 0

Apply Newton's second law to the person's motion:

F = ma

F = net force, m = mass, a = acceleration

Given values:

m = 50.8kg, a = 3.50m/s²

Plug in and solve for F:

F = 50.8(3.50)

F = 178N

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Answer:

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Explanation:

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W=\Delta K\\W=K_f-K_i\\W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}

The box is initially at rest, so v_i=0. Solving for v_f:

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3 years ago
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Answer:

n = \frac{c}{v}

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