How much force does it take to accelerate a 50.8 kg person at 3.50 m/s^2?
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Answer
Mass m = 78 kg
Vertical height in each stage h = 11 m
(a).
Initial speed u = 0
Final speed v = 1.1 m / s
a = 0.055 m/s²
Work done
(b).Work done
W_b = 78× 9.8× 11
c)
Work done
Where V = final speed
= 0
v = 1.1 m / s
for deceleration a = -0.055 m/s²
now,
W_c = 545.75 × 11
Answer: 24
Explanation:
Given the following equation:
Where is the number of mushrooms in a pizza and
the number of pizzas.
If we know the restaurant will make 8 pizzas (), then:
This is the needed number of mushrooms for 8 pizzas