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levacccp [35]
2 years ago
15

Due to the friction between a tire and the road surface, the temperature of the air inside a tire increases as one drives. If th

e tire pressure is 37 psi when the car is in the driveway at 25° C, What is the pressure of the tire when the temperature increases to 50° C?
Physics
1 answer:
inysia [295]2 years ago
5 0

Answer:

40.10 atm .

Explanation:

Here volume of tire is assumed to be nearly constant .

Modified gas law ,

P₁ / T₁ = P₂ / T₂

37 / ( 273 + 25 ) = P₂ / ( 273 + 50)

37 / 298 = P₂ / 323

P₂ = 37 x 323 / 298

= 40.10 atm .

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The coordinates of a bird flying in the xy plane are given by x(t)=αt and y(t)=3.0m−βt2, where α=2.4m/s and β=1.2m/s2. Calculate
yuradex [85]
     The derivative of the function space as a function of time is equal to a function of speed as a function of time.

x(t)=2.4t \\  \frac{x(t)}{t}=t \\ v_{x}(t)=t \\  \\ y(t)=3-1.2\times t^2 \\  \frac{y(t)}{t}=1.2\times2t \\ v_{y}(t)=2.4t
   
     The velocity vector is given by the vector sum of the velocities of  both axes.

v_{R}^2(t)=v_{x}^2(t)+v_{y}^2(t) \\ v_{R}^2(t)=(t)^2+(2.4t)^2 \\ \boxed {v_R(t)=2.6t}

If you notice any mistake in my english, please let me know, because I am not native.

4 0
3 years ago
Read 2 more answers
The least count of stopwatch is 0.2s.The time of 20 oscillations of a pendulum was measured to be 25s.Find the percentage error
Svet_ta [14]

Answer:

0.8%

Explanation:

We are given;

Number of oscillations; n = 20

Time taken; t = 25 s

Formula for period of oscillation;

T = t/n = 25/20 = 1.25 s

We are told that the least count is 0.2 s. Thus, error is; ΔT = 0.2 s

percentage error in the measurement of time is given by;

(0.2/(20 × 1.25)) × 100% = 0.8%

4 0
2 years ago
The answer is not B.
mezya [45]

Answer:

D

Explanation:

15m/ s

i hope this helps

4 0
1 year ago
Two objects (42.0 and 21.0 kg) are connected by a massless string that passes over a massless, frictionless pulley. The pulley h
Kazeer [188]

Answer:

a = 3.27 m/s²

T = 275 N

Explanation:

Given that:

Mass m₁ = 42.p0 kg

Mass m₂ = 21.0 kg

Consider both masses to be in a whole system, then:

The acceleration can be determined as:

(m_1+m_2)a = g(m_1-m_2)

Making acceleration the subject in the above formula;

a =\dfrac{g(m_1-m_2)}{(m_1+m_2)}

a =\dfrac{9.8(42.0-21.0)}{(42.0+21.0)}

a =\dfrac{9.8(21.0)}{(63.0)}

a =\dfrac{205.8}{(63.0)}

a = 3.27 m/s²

in the string, the tension is calculated using the formula:

T = \dfrac{2m_1m_2g}{(m_1+m_2)}

T = \dfrac{2(42)(21)(9.81)}{(42+21)}

T = \dfrac{17304.84}{63}

T = 274.68 N

T ≅ 275 N

8 0
2 years ago
The whooping crane (Grus americana) is the tallest bird native to North America. It almost went extinct in the 1900s; in 1938, t
grin007 [14]

Answer:

The value  is   a =  2.7183

Explanation:

From the question we are told that

   The  relationship between the number of whooping cranes and the number of decades is ln N =  2.85 + 0.039t

  The  exponential relationship is  N  =  na^{kt}

Now from the given equation we have that

       N  =   e^{2.85 + 0.039t}

       N  =  17.29 e^{0.039t}

So comparing this equation obtained an the given  exponential relationship we have that

      n = 17.29

       k  =  0.039

        a =  e =  2.7183

        a =  2.7183

 

7 0
2 years ago
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