Answer: yes
Explanation: When you mix an acid an a base the color it showing a chemical change.
Answer:
Scientists use a two-name system called a Binomial Naming System. Scientists name animals and plants using the system that describes the genus and species of the organism. The first word is the genus and the second is the species. The first word is capitalized and the second is not.
Explanation:
Answer:
1. Elements
2. one
3. properties
4. Chemical
5. metal
6. non-metal
7. metalloids
8. Compounds
9. one
10. more
11. components
12. chemical process
Explanation:
In the given paragraph a brief about the difference between element and compound is given.
Elements are made up of the same type of atoms and each element is made up of one atom, that is they cannot be broken down into any other substance. Each element is different from each other due to its properties, though some have the same physical properties but are different in chemical properties. Elements can be classified as metals such as iron and silver, non-metals such as oxygen and hydrogen, and metalloids such as boron and silicon.
Compounds are a combination of one or more elements such as water and salt. Compounds can be easily broken down into components through a chemical process.
Hence, the correct answer is:
1. Elements
2. one
3. properties
4. Chemical
5. metal
6. non-metal
7. metalloids
8. Compounds
9. one
10. more
11. components
12. chemical process
B hibernation but it deppends on the animal
Answer:
concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm
Explanation:
ppm (parts per million) concentration is defined as the mass (in milligrams) of a substance dissolved in one liter of solution.
In our case we have:
mass of MgBr₂ = 12.41 g
volume of water (which is equal to the final solution volume) = 2.55 L
Now we devise the following reasoning:
if 12.41 g of MgBr₂ are dissolved in 2.55 L of water
then X g of MgBr₂ are dissolved in 1 L of water
X = (1 × 12.41) / 2.55 = 4.867 g of MgBr₂
if in 184 g (1 mole) of MgBr₂ we have 160 g of Br⁻
then in 4.867 g of MgBr₂ we have Y g of Br⁻
Y = (4.867 × 160) / 184 = 4.232 g of bromide (Br⁻)
4.232 g of bromide (Br⁻) = 4234 mg of bromide (Br⁻)
concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm
