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Alexus [3.1K]
3 years ago
8

What describes Rutherford’s model of the atom?

Chemistry
1 answer:
HACTEHA [7]3 years ago
8 0
Rutherford's model shows that an atom is mostly empty space, with electrons orbiting a fixed, positively charged nucleus in set, predictable paths. ... It was after this that Rutherford began developing his model of the atom.
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Compared to a solid, the molecular bonds of a liquid are.
slava [35]
The answer is B) weak
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3 years ago
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What Mendel called factors are now called
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They are now called genes. 
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3 years ago
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6.00g of gold was heated from 20.0c to 22.0c. How much heat was applied to the gold
Alinara [238K]
6 x .129 x 2= 1.55J
q = mass x specific heat x delta T.
5 0
2 years ago
Using the equation below, if you have 4.3 mol of nitrogen tribromide and
ankoles [38]

Answer:

sodium hydroxide is the limiting reactant

Explanation:

The first step is usually to put down the balanced reaction equation. This is the first thing to do when solving any problem related to stoichiometry. The balanced reaction equation serves as a guide during the solution.

2NBr3 + 3NaOH = N2 + 3NaBr + 3HOBr

Let us pick nitrogen gas as our product of interest. Any of the reactants that gives a lower number of moles of nitrogen gas is the limiting reactant.

For nitrogen tribromide

From the balanced reaction equation;

2 moles of nitrogen tribromide yields 1 mole of nitrogen gas

4.3 moles of nitrogen tribromide will yield 4.3 ×1/ 2 = 2.15 moles of nitrogen gas

For sodium hydroxide;

3 moles of sodium hydroxide yields 1 mole of nitrogen gas

5.9 moles of sodium hydroxide yields 5.9 × 1/ 3= 1.97 moles of nitrogen gas

Therefore, sodium hydroxide is the limiting reactant.

8 0
2 years ago
The specific heat of copper is 0.40 joules/ g °c. How much heat is needed in joules to change the temperature of a 55 gram subst
Snezhnost [94]

Answer : The amount of heat needed is, 1188 J

Explanation :

Formula used :

q=m\times c\times (T_2-T_1)

where,

q = heat needed = ?

m = mass of copper = 55 g

c = specific heat capacity of copper = 0.40J/g^oC

T_1 = initial temperature = 20.0^oC

T_2 = final temperature = 74.0^oC

Now put all the given values in the above formula, we get:

q=55g\times 0.40J/g^oC\times (74.0-20.0)^oC

q=1188J

Thus, the amount of heat needed is, 1188 J

3 0
3 years ago
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