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sineoko [7]
3 years ago
14

The caloric content of 0.50 cup of cottage cheese is 1.10 x 102 kcal. This is the amount of energy released when 0.50 cup of cot

tage cheese is burned or metabolized by the body. The average slow walker requires 226 kcal of energy to walk one mile. How many cups of cottage cheese would provide enough energy for this walker to walk from Gannon’s Zurn Science Center to the Millcreek Mall (19.3 km)?
Chemistry
1 answer:
V125BC [204]3 years ago
3 0

Answer:

A piece of unknown solid substance weighs 437.2 g, and requires 8460 J to increase its temperature from 19.3 °C to 68.9 °C.

What is the specific heat of the substance?

If it is one of the substances found in Table 8.1.1, what is its likely identity?

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Which statement is true about compounds? They do not form living things. They do not form nonliving things. They are formed when
oksano4ka [1.4K]

Answer:

The true statement is:

They are formed when atoms of different elements combine.

Explanation:

Compounds are formed when atoms of different elements combine.

Atoms of different elements combine with each other to attain stable electronic configuration.

The atoms can combine with each other in two different ways:

1) By sharing the electrons

2) By exchanging electrons

When they share electrons with each other, they form a covalent bond.

When they exchange electrons, they form an ionic bond.

3 0
3 years ago
What is the [ H3O+] of a solution with pH = (8.50x10^0)? enter your answer in scientific notation and with three sig figs.
erastovalidia [21]

Answer:

[H₃O⁺] = 3.162 × 10⁻⁹ moles / liter

Explanation:

The pH is calculated with the formula:

pH = -lg[H₃O⁺]

From here the concentration of hydronium ion (H₃O⁺) will be:

[H₃O⁺] = 10^{-pH}

[H₃O⁺] = 10^{-8.5}

[H₃O⁺] = 3.162 × 10⁻⁹ moles / liter

3 0
3 years ago
Read 2 more answers
For the reaction o(g) + o2(g) → o3(g) δh o = −107.2 kj/mol given that the bond enthalpy in o2(g) is 498.7 kj/mol, calculate the
Aneli [31]
The reaction;
O(g) +O2(g)→O3(g), ΔH = sum of bond enthalpy of reactants-sum of food enthalpy of products.
ΔH = ( bond enthalpy of O(g)+bond enthalpy of O2 (g) - bond enthalpy of O3(g)
-107.2 kJ/mol = O+487.7kJ/mol =O+487.7 kJ/mol +487.7kJ/mol =594.9 kJ/mol
Bond enthalpy (BE) of O3(g) is equals to 2× bond enthalpy of O3(g) because, O3(g) has two types of bonds from its lewis structure (0-0=0).
∴2BE of O3(g) = 594.9kJ/mol
Average bond enthalpy = 594.9kJ/mol/2
=297.45kJ/mol
∴ Averange bond enthalpy of O3(g) is 297.45kJ/mol.
8 0
3 years ago
The ions in most ionic compounds are organized into a
Igoryamba
They are organized into crystals hope i helped
5 0
3 years ago
The picture compound has which bond?
Marina CMI [18]

Answer:

something

Explanation:

4 0
3 years ago
Read 2 more answers
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